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inna [77]
2 years ago
7

Help please need to turn In tomorrow

Mathematics
1 answer:
qwelly [4]2 years ago
7 0
21/72
then simplified 
= 7/24
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Triangle A″B″C″ is formed by a reflection over x = 1 and dilation by a scale factor of 2 from the origin. Which equation shows t
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Answer:

segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13

Step-by-step explanation:

Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).

1. Reflection over x = 1 maps vertices A, B and C as follows

  • A(-3,3)→A'(5,3);
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2. Dilation by a scale factor of 2 from the origin has the rule

(x,y)→(2x,2y)

So,

  • A'(5,3)→A''(10,6);
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See attached diagram for details

Note that

A''B''=2AB\\ \\A''C''=2AC\\ \\B''C''=2BC,\\ \\AB=\sqrt{(-3-1)^2+(3-(-3))^2}=\sqrt{16+36}=\sqrt{52}=2\sqrt{13}

so

\dfrac{AB}{A''B''}=\dfrac{2\sqrt{13}}{2\cdot 2\sqrt{13}}=\dfrac{\sqrt{13}}{2\sqrt{13}}

7 0
3 years ago
Graph and label Point H at 1.5 , negative 6 thirds
andre [41]
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3 years ago
The total surface area of a cone whose radius is 2 r and slant height 2l is
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Answer:

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Step-by-step explanation:

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A=\pi \times 2r(2l+2r)\\\\A=2\pi r(2l+2r)\\\\=2\pi r \times 2(l+r)\\\\=4\pi r(l+r)

Hence, the total surface area of the cone is 4\pi r(l+r).

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The correct answer should be A not 100% sure

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Convert x = 4 to polar form
dezoksy [38]

Answer: r = 4 sec θ

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