Answer:
Frequency of p ![= 0.684](https://tex.z-dn.net/?f=%3D%200.684)
Frequency of p ![= 0.316](https://tex.z-dn.net/?f=%3D%200.316)
Number of individuals with homozygous dominant (AA) ![= 47](https://tex.z-dn.net/?f=%3D%2047)
Number of individuals with heterozygous (Aa)![= 43](https://tex.z-dn.net/?f=%3D%2043)
Number of individuals with homozygous recessive (aa) ![= 10](https://tex.z-dn.net/?f=%3D%2010)
Explanation:
Out of 100 people, 10 have albino skin (aa)
So, the frequency of homozygous recessive individuals
is ![\frac{10}{100} = 0.1](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B100%7D%20%3D%200.1)
Now, q will be
![= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7Bq%5E%7B2%7D%20%7D%20%3D%20%5Csqrt%7B0.1%7D%20%5C%5C%3D%200.316)
As per Hardy Weinberg's equation -
![p + q = 1](https://tex.z-dn.net/?f=p%20%2B%20q%20%3D%201)
Substituting the value of q in above equation, we get -
![p + 0.316 = 1p = 1 -0.316\\p = 0.684](https://tex.z-dn.net/?f=p%20%2B%200.316%20%3D%201p%20%3D%201%20-0.316%5C%5Cp%20%3D%200.684)
Now the frequency of homozygous dominant (AA) will be
![p^{2} = 0.684^{2} \\= 0.467](https://tex.z-dn.net/?f=p%5E%7B2%7D%20%3D%200.684%5E%7B2%7D%20%5C%5C%3D%200.467)
Hence, out of 100 people
people are homozygous dominant (AA)
Like wise out of 100 people
people are homozygous recessive (aa)
As per As per Hardy Weinberg's equation-
![p^{2} + q^{2} + 2pq = 1\\](https://tex.z-dn.net/?f=p%5E%7B2%7D%20%2B%20q%5E%7B2%7D%20%2B%202pq%20%3D%201%5C%5C)
Substituting the values in above equation, we get -
![0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433](https://tex.z-dn.net/?f=0.467%20%2B%200.316%20%2B%202pq%20%3D%201%5C%5C2pq%20%3D%201%20-%28%200.467%2B%200.1%29%5C%5C2pq%20%3D%200.433)
So, out of 100 people
people are heterozygous (Aa)