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omeli [17]
3 years ago
6

HELP PLEASE thank you ​

Mathematics
1 answer:
brilliants [131]3 years ago
4 0
They are similar
3:3:5:5
4:4:6:6
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- How many odd 2-digit positive odd integers greater than 50 are there?
garri49 [273]

Answer:

To be greater than 20, we can either use values of 2 through 9 for the first digit, which is a total of 8 digits. For the second digit, in order to be even, we can use 1, 3, 5, 7, or 9. ( 5 options). Multiply together and we have the total number of possibilities.

8 0
4 years ago
Read 2 more answers
Write the coordinates of the vertices after a translation 6 units left and 2 units down.
jenyasd209 [6]

Answer:

Answer below.

Step-by-step explanation:

K'(-7,0) L'(-5,3) M'(-7,4) N'(-9,3)

4 0
3 years ago
Mrs. Taylor would like to construct a confidence interval for the number of highlighters that are borrowed and not returned in h
Furkat [3]

The confidence interval at a 90% confidence level is (60.9%,75.1%) if in the end of a semester, she loaned 115 highlighters and found that 68% were not returned option (A) is correct.

<h3>What is the margin of error(MOE)?</h3>

It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.

The formula for finding the MOE:

\rm MOE = Z\times{\sqrt \dfrac{p(1-p)}{n}\\

Where   Z is the z-score at the confidence interval

            p is the population proportion

            n is the number of samples.

We have p = 68% = 0.68

n = 115

Z score for 90% confidence interval = 1.64

\rm MOE = 1.64\times{\sqrt \dfrac{0.68(1-0.68)}{115}\\

MOE = 0.071

So the confidence interval will be:

= (0.68-0.071, 0.68+0.071)

= (0.609, 0.751)  or

= (60.9%, 75.1%)

Thus, the confidence interval at a 90% confidence level is (60.9%,75.1%) if in the end of a semester, she loaned 115 highlighters and found that 68% were not returned option (A) is correct.

Learn more about the Margin of error here:

brainly.com/question/13990500

#SPJ1

7 0
2 years ago
When constructing a prependicular bisector why must the compass opening be greater than 1/2 the length of the segment ?
Tomtit [17]

Because otherwise the two circles you build wouldn't have any intersection!

You have to draw two circles, centered at the endpoints of the segment, and connect their intersection.

If the radii are less than half the length of the circle, the circles will have no interserction.

5 0
3 years ago
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths.
shtirl [24]

Answer:

HC=\sqrt{3}

Step-by-step explanation:

Let HC=x, it is given that AH=3HC, then AH=3x.

Since, from the given figure, ΔABC is similar to ΔBHC and ΔABC is similar to ΔABH.

Therefore, ΔABH is similar to ΔBHC, hence using the similarity conditions,

\frac{HC}{BH}=\frac{BH}{AH}

\frac{x}{3}=\frac{3}{3x}

3x^{2}=9

x^{2}=3

x=\sqrt{3}

Hence, HC=\sqrt{3}.


7 0
4 years ago
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