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NemiM [27]
3 years ago
10

sharon earns $25 per item she sells plus a base salary of $100 per week. write and solve an inequality to find how many items sh

e must sell to earn at least $700 per week
Mathematics
1 answer:
Andrei [34K]3 years ago
4 0

Answer:

she must sell 24 items a week to make $700 per week

Step-by-step explanation:

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In triangle ABC below, which trigonometric ratio equals 3/2?
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If f(x)=4^x-8 and g(x)=5x+6 find (f+g)(x) ANSWER ASAP PLS
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<h3>Answer: 4^x+5x-2</h3>

Add up the equations and combine any like terms. In this case, the like terms are -8 and +6 which combine to -2. Everything else is unlike terms so you leave them as is.

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4 years ago
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Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In x = 3
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The solution is:

x = e^{3} = 20.09

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\ln{x} = 3

It already is in the desired format.

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7 0
3 years ago
Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba
Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let <em>X</em> = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = <em>p</em> = 0.05.

The sample of items selected is of size, <em>n</em> = 150.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and <em>p</em> = 0.05.

According to the Central limit theorem, if a sample of large size (<em>n</em> > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: \mu_{\hat p}= p=0.05

The standard deviation of this sampling distribution is: \sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178

If 10 of the 150 items produced are unacceptable then the probability of this event is:

\hat p=\frac{10}{150}=0.067

Compute the value of P(\hat p\leq 0.067) as follows:

P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315

*Use a <em>z</em>-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0
3 years ago
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