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slavikrds [6]
3 years ago
8

An athlete who uses blood from another person for blood doping runs the risk of contracting a blood-borne disease because

Biology
2 answers:
Veronika [31]3 years ago
6 0
Pathogens can exist in blood and then can be passed the transfusions
Salsk061 [2.6K]3 years ago
4 0

Answer:

pathogens can exist in the blood and be passed on through transfusions

Explanation:

Although the risk of transfusion-transmitted infections today is lower than before, the supply of blood transfusions remains subject to contamination with known and unidentified human pathogens. This can cause these pathogens to be transmitted from one person to another. That is, the risk of infections by blood transfusions has been reduced over the years, but not eliminated.

This indicates that athletes who use someone else's blood for blood doping are at risk of contracting a blood-borne disease because pathogens can exist in the blood and then transfusions can be passed on.

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5 0
3 years ago
A certain buffer is made by mixing a weak acid HA and its conjugate base A–. When HA is present at a concentration of 0.5 mM and
MAVERICK [17]

Answer:The ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

Explanation:

The dissociation constant for formic acid = K_a=1.8\times 10^{-4}

Concentration of HA= 0.5 mM

Concentration of A^-= 0.1 mM

pH = 6.16

First we have to calculate the value of K_a.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[A^-}{[HA]}

Now put all the given values in this expression, we get:

6.16=pK_a+\log (\frac{[0.1]}{0.5})

pK_a=6.86

To calculate the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02.

Using Henderson Hesselbach equation :

7.02=6.86+\log \frac{[A^-]}{[HA]}

7.02=6.86+\log \frac{[A^-]}{[HA]}

\frac{[A^-]}{[HA]}=1.44

\frac{[HA]}{[A^-]}=0.69

Thus the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

7 0
3 years ago
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