Answer:
3.
1.x=√(15²-12²)=√81=9
2.x=√(6²+6²)=6√2
3.c=√(√19²-√7²)=√(19-7)=√12
Step-by-step explanation:
4.h=10
a=b=x
we have
by using Pythagoras law
h²=x²+x²
100=2x²
x²=50
x=√50=5√2
both legs =5√2
Answer:
la variable que se debe ingresar en el programa corresponde a: c. edad
Step-by-step explanation:
Las variables cuantitativas son aquellas que toman valores numéricos y se clasifican en variables cuantitativas discretas que son las que sólo pueden asumir un número limitado de valores en un determinado rango, como por ejemplo, el número de carros que posee una persona y variables cuantitativas continuas que pueden tomar cualquier valor en un rango específico, como por ejemplo, el peso de un objeto. De acuerdo a estas definiciones, la respuesta es que la variable que se debe ingresar en el programa corresponde a: edad porque es una variable discreta dado que se registra en números enteros y no acepta cualquier valor en un intervalo específico.
Las otras opciones no son correctas porque la nacionalidad y el nivel de escolaridad no son variables cuantitativas y la altura es una variable cuantitativa continua.
Start circle: πd = (3.14)(19) = 59.7
Move diagonally to the circle with the radius of 6.2.
Second circle: 2πr = 2(3.14)(6.2) = 39
Move upwards to the circle with the radius of 10.5
third circle: 2πr = 2(3.14)(10.5) = 66
Move right to the circle with the diameter of 16.6
Fourth circle: πd = (3.14)(16.6) = 52.2
Move down to the circle with the diameter of 7.7
fifth circle: πd = (3.14)(7.7) = 24.2
Move down to the circle with the diameter of 50
Sixth circle: πd = (3.14)(50) = 157.1
Move left to the circle with the radius of 11.8
Seventh circle: 2πr = 2(3.14)(11.8) = 74.1
Move down to the circle with the radius of 38
Eight circle: 2πr = 2(3.14)(38) = 238.8
Move right to the circle with the diameter of 1.1
ninth circle: πd = (3.14)(1.1) = 3.5
Move right to the circle with the radius of 14.8
10th circle = 2πr = 2(3.14)(14.8) = 93
Move up to the end.
Hope this helps :)
Answers:
1) 
2) 
Step-by-step explanation:
In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:
<u>Addition:
</u>
If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).
For example, the addition of these two binomials is:
Similarly, the addition of two complex numbers is:
Here the complex part is the number with the 
<u>Multiplication:
</u>
If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that 
.
For example, the multiplication of these two binomials is:
Similarly, the multiplication of two complex numbers is:
Answer:
No solutions
Step-by-step explanation:
|-2x-10| + 4 = 2
Subtract 4 from each side
|-2x-10| + 4-4 = 2-4
|-2x-10| = -2
The absolute value is negative so there are no solutions.
Absolute values are always positive, so they cannot be negative.
