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Damm [24]
3 years ago
10

z varies inversely with the product of x and y. when x=2 and y=4, z=0.5. what is the value of z when x=4 and y=9? please help, i

've tried different things and i can't seem to get the correct answer. my choices are a: 45/2 b: 40/9 c:40 d: 1/9
Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0
If z varies inversely with the product of x and y:
z = k/ (x*y)
0.5 = k/(2*4)
0.5 = k/ 8
k = 0.5 * 8
k = 4.
Therefore, when x = 4 and y = 9:
z = 4 / (4*9) = 4/36 = 1/9
Answer: D ) 1/9 
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A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
3 years ago
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7 0
3 years ago
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ElenaW [278]

Answer:

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Step-by-step explanation:

25° is really the only logical answer.

8 0
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