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3 years ago

If f(x) = 1-x2 and g(x) = 1 - x which is the rule of function (f – g)(x)?

Mathematics

1 answer:

V125BC [204]3 years ago

6 0

Answer:

-x^2 +x

Step-by-step explanation:

f(x) = 1-x^2

g(x) = 1 - x

f(x) - g(x) = 1-x^2 - (1 - x )

Distribute the minus sign

= 1-x^2 -1 +x

Combine like terms

= -x^2 +x

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Solve for y in terms of x<br> 3(x – 7) + 7y = 10x

MAXImum [283]

Answer:

solve for y is y = x + 3

Solve for x is x = − 3 + y

Step-by-step explanation:

4 0

2 years ago

2x-1-(-x+3) = 6-2x SHOW STEPS....DUE TODAY

sveta [45]

Answer:

x=2

Step-by-step explanation:

Simplify both sides of the equation.

2x−1−(−x + 3)=6−2x

(Distribute the Negative Sign)

2x−1 + −1(−x + 3)=6−2x

2x + −1 + −1(−x) + (−1)(3)=6−2x

2x + −1 + x + −3=6−2x

2x + −1 + x + −3=6 + −2x

(Combine Like Terms)

(2x + x) + (−1 + −3)=−2x+6

3x + −4=−2x + 6

3x−4=−2x + 6

Add 2x to both sides.

3x−4 + 2x=−2x + 6 + 2x

5x−4=6

Add 4 to both sides.

5x−4 + 4=6 + 4

5x=10

Divide both sides by 5.

5x/5=10/5

x=2

5 0

2 years ago

What is the pattern 1 white bead then three blue beads then 1 white bead

Keith_Richards [23]

1 white bead 3 blue beads 1 white bead 3 blue beads 1 white bead 3 blue beads.... it just keeps going

6 0

3 years ago

Two fair coins are flipped. Given that at least one coin lands on a head, calculate the probability of one head and one tail. Wr

Greeley [361]

The probability of one head and one tail is 2/3.

<u>Step-by-step explanation</u>:

The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities

Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities

To calculate the probability of one head and one tail,

Probability = required events / Total events

Probability = 2/3

8 0

3 years ago

University degree requirements typically are different for Bachelor of Science degrees and Bachelor of Arts degrees. Some studen

ira [324]

Answer:

A. 0.1

B. 0.8

C. 0.5

Step-by-step explanation:

Given:

P(Science) = 0.3

P(Arts) = 0.6

P(none) = 0.2

From the above, it is understood that the events are independently events; meaning that the probability that a students gets a Bachelor of Science degree does not affect the probability of the same student getting a Bachelor of Arts degree.

A. The probability that a student gets a Bachelor of Science and Bachelor of Arts degree

Let P(Arts and Science) = the probability that a student gets a Bachelor of Arts degree and Bachelor of Science degree

For independent events,

P(A) + P(B) - P(A and B) + P(none)= 1

If we translate the above formula to suit our needs, we have something like this

P(Science) + P(Arts) - P(Arts and Science) + P(none) = 1

P(Arts) + P(Science) - P(Arts and Science) + P(none) = 1

From this, we have

0.3 + 0.6 - P(Arts and Science) + 0.2 = 1

1.1 - P(Arts and Science) = 1

-P(Arts and Science) = 1 - 1.1

-P(Arts and Science) = -0.1

P(Arts and Science) = 0.1

B. The probability that a student gets a Bachelor of Science or Bachelor of Arts degree

For independent events

P(A or B) = P(A) + P(B) - P(A and B)

So, P(Arts or Science) = P(Arts) + P(Science) - P(Arts and Science)

P(Arts or Science) = 0.3 + 0.6 - 0.1

P(Arts or Science) = 0.8

C. The probability that a student gets only Bachelor of Arts

P(A only) = P(A) - P(A and B)

P(Arts) = P(Arts) - P(Arts and Science)

P(Arts) = 0.6 - 0.1

P(Arts) = 0.5

6 0

3 years ago