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rjkz [21]
3 years ago
10

In a raffle, 1,000 tickets are sold for $2 each. One ticket will be randomly selected and the winner will recieve a laptop compu

ter vauled at $1200. What is the expected value for a person that buys one ticket?
Mathematics
1 answer:
Kryger [21]3 years ago
7 0

Answer:

$ 1.2

Step-by-step explanation:

The first thing is to define the expected value of the ticket that would be the sum of the value for all event probabilities.

That is, if you buy 1 ticket, for each participant the probabilities are:

1. 1/1000 to get a $ 1,200 item

2. 999/1000 to get nothing ($ 0).

That is to say:

(1/1000) * $ 1200 + (999/1000) * $ 0 = (1/1000) * $ 1200 = $ 1.2

Therefore, the expected value is $ 1.2, this means that in reality each participant pays $ 0.8 more than the ticket is worth

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6

Step-by-step explanation:

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What are the answers to 18-38
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Find the equation of the line with slope 3/7 and that passes through the point (14, 0). Write your answer in the form y = mx + b
Allushta [10]

Answer:

y = 3/7x - 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Slope <em>m</em> = 3/7

Point (14, 0)

<u>Step 2: Find y-intercept </u><em><u>b</u></em>

  1. Substitute:                    0 = 3/7(14) + b
  2. Multiply:                        0 = 6 + b
  3. Isolate <em>b</em>:                       -6 = b
  4. Rewrite:                         b = -6

<u>Step 3: Write linear equation</u>

y = 3/7x - 6

7 0
2 years ago
Find the slope of the line through the points (-5, 2) and (5,0).
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4 0
3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It
Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0
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