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rjkz [21]
4 years ago
10

In a raffle, 1,000 tickets are sold for $2 each. One ticket will be randomly selected and the winner will recieve a laptop compu

ter vauled at $1200. What is the expected value for a person that buys one ticket?
Mathematics
1 answer:
Kryger [21]4 years ago
7 0

Answer:

$ 1.2

Step-by-step explanation:

The first thing is to define the expected value of the ticket that would be the sum of the value for all event probabilities.

That is, if you buy 1 ticket, for each participant the probabilities are:

1. 1/1000 to get a $ 1,200 item

2. 999/1000 to get nothing ($ 0).

That is to say:

(1/1000) * $ 1200 + (999/1000) * $ 0 = (1/1000) * $ 1200 = $ 1.2

Therefore, the expected value is $ 1.2, this means that in reality each participant pays $ 0.8 more than the ticket is worth

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Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29
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Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ \frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

⇒ \frac{15}{Sin 29} = \frac{20}{sin B}

Using value of sin 29°

⇒ \frac{15}{0.49} = \frac{20}{sin B}

Cross multiplying both side.

⇒ Sin B= \frac{20\times 0.49}{15} = 0.65

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ 29+41+B= 180

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

\frac{b}{SinB} = \frac{c}{SinC}

⇒\frac{20}{sin41} = \frac{C}{sin110}

Using the value of sine and cross multiplying both side.

⇒ C= \frac{20\times 0.94}{0.65} = 28.92

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= (15+20+28.92)= 63.9

∴ Perimeter of triangle= 63.9 units

7 0
3 years ago
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