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3 years ago

Solve the system. y= 3x2−2x+3 y = x + 3 The solutions are (,) and (,).

Mathematics

1 answer:

photoshop1234 [79]3 years ago

8 0

Answer:

(0,3) and (1,4)

Step-by-step explanation:

Given that:

y= 3x2−2x+3 ------------- eq1

y = x + 3 ------------------ eq2

Putting value from eq2 to eq1

x + 3 = 3x2−2x+3

3x2−2x+3 - x - 3 = 0

3x2−3x = 0

Taking 3 common

x2 - x = 0

x(x-1)= 0

x = 0 and x = 1

Now put value in eq2

y = 0 + 3 and y= 1 + 3

y = 3 and y = 4

So solution sets are:

(0,3) and (1,4)

i hope it will help you!

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What are the domain and range of the inequality y < sqrt x+3+1

love history [14]

Given:

The inequality is:

$y$

To find:

The domain and range of the given inequality.

Solution:

We have,

$y$

The related equation is:

$y=\sqrt{x+3}+1$

This equation is defined if:

$x+3\geq 0$

$x\geq -3$

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

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