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Damm [24]
3 years ago
14

A rectangular picture frame has the dimensions shown in

Mathematics
2 answers:
Ber [7]3 years ago
7 0
The perimeter of the frame would be 86
Colt1911 [192]3 years ago
5 0

Answer:

86

Step-by-step explanation:

86

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Please find the value of x and explain to me, I will mark brainliest<br>​
ser-zykov [4K]

Answer:

The value of X is always 1

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2 years ago
Given: -1/2x&gt;6. Choose the solution set
Step2247 [10]

Answer:

B

Step-by-step explanation:

multiply both sides by 2 to eliminate the fraction

- x > 12

multiply both sides by - 1

Remembering to reverse the inequality symbol as a consequence

x < - 12 ← reverse symbol

⇒ { x | x ∈ R, x < - 12 } → B


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2 years ago
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Which of the following accurately depicts the transformation of y= x^2 to the function shown below? y=2(x-3)^2+5
sweet [91]

Answer:

Which of the following accurately depicts the transformation of y= x^2 to the function shown below? y=2(x-3)^2+5

A. Shift left 3 units, shrink vertically to 1/2 of the original height, then shift up 5 units.

B. Shift right 3 units, stretch vertically by a factor of 2, then shift up 5 units.

C. Shift up 3 units, stretch horizontally by a factor of 2, then shift left 5 units.

D. Shift 5 units right, stretch vertically by a factor of 3, then shift up 2 units.

Step-by-step explanation:

For f(x) = 4x+1 and g(x)= x^2-5, find (f/g) (x).

6 0
2 years ago
Solve -7x^2+x+9=-6x quadratic formula
myrzilka [38]

Answer:

-7x^2+x+9=-6x

-7x^2+x+9+6x=-6x+6x

-7x^2+7x+9=0

quadratic\: formula

x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\left(-7\right)\cdot \:9}}{2\left(-7\right)}

\sqrt{-7^{2} -4(-7)\times9} =\sqrt{301}

x_{1,\:2}=\frac{-7\pm \sqrt{301}}{2\left(-7\right)}

\frac{-7+\sqrt{301}}{2\left(-7\right)}

=\frac{-7+\sqrt{301}}{-2\cdot \:7}

=\frac{-7+\sqrt{301}}{-14}

\frac{-7-\sqrt{301}}{2\left(-7\right)}

=\frac{-7-\sqrt{301}}{-2\cdot \:7}

=\frac{-7-\sqrt{301}}{-14}

answer=\frac{7+\sqrt{301}}{14}

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7 0
3 years ago
What is the elapesed time from 10:30pm to 12:15 am?
ehidna [41]
1 Hour and 45 minutes.
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3 years ago
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