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garik1379 [7]
3 years ago
7

Can someone please help me with this

Mathematics
2 answers:
galben [10]3 years ago
4 0
Yes thats a function, it passes the vertical line test!
svet-max [94.6K]3 years ago
4 0

Answer:

Yes it is a function

Step-by-step explanation:

If it passes the vertical & horizontal line test, then it is a one to one. if it passes the vertical line test but fails the horizontal, then it is a function, but not one to one.

Hoped this helped you!

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PLEASE HELP ME THANKS IF u do
garik1379 [7]

Answer:

The third one

Step-by-step explanation:

It can't be the first one since the peak is 4 since it is the highest

It can't be the second one because the data is all different

It could be the third one since their are gaps

And It can't be the fourth one because the range is 7

So it must be the third one

6 0
3 years ago
What is the range of the function y=\cos 2x ?
sattari [20]
All real numbers is the answer
7 0
4 years ago
I'm back I need help with both of these questions
AlexFokin [52]
1st
90+55+x=180 (Angles inside a triangle equal 180 degrees) Solve for x
x = 35 degrees

2nd
2 non-adjacent angle in a triangle is equal to the exterior angles, therefore

25 + x + 15 = 3x + 10    Solve for x
  40 + x = 3x + 10
-10   -1x  -1x  -10

<u>30 = 2x</u>
     2

x = 15 degrees
Therefore angle ABC is x + 15 where x + 15

Therefore angle ABC = 30 degrees

Who ever hand wrote in those degrees/equations didn't really think it out because < A + <B should be greater than 90 not less than 90 
7 0
4 years ago
Find the exact value of sin 30 degrees
Juli2301 [7.4K]

Answer:

\sin( 30 )  =  \frac{1}{2}  = 0.5

5 0
3 years ago
(3a^3-5b^3)+blank a^3+blank b^3=(a^3+b^3)
lions [1.4K]

Answer:

(3a³-5b³)+ (-2)a³ +6b³=(a³+b³)

Step-by-step explanation:

First,  lets remove the brackets.  There is no "-" before the brackets, so we can just remove them at all.

3a³-5b³+ ...a³ +...b³=a³+b³

Now we can joint similar monoms (with variable a)  ( and with variable b) in the left side of equation

3a³+...a³ -5b³ +...b³=a³+b³

Now we can notice that 3a³+...a³=a³    (1)  and

-5b³ +...b³=b³    (2)

Lets find deduct 3a³ from both sides of (1)

...a³= a³-3a³

...a³= -2a³  So instead ... we have to type -2 (-2 is negative sowe type -2 in brackets).

Similarly   lets add 5b³ to both sides of (2)

-5b³ +...b³=b³

-5b³ +5b³ +...b³=b³+5b³

...b³=6b³ So instead ... we have to type 6.

6 0
3 years ago
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