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garik1379 [7]
3 years ago
7

Can someone please help me with this

Mathematics
2 answers:
galben [10]3 years ago
4 0
Yes thats a function, it passes the vertical line test!
svet-max [94.6K]3 years ago
4 0

Answer:

Yes it is a function

Step-by-step explanation:

If it passes the vertical & horizontal line test, then it is a one to one. if it passes the vertical line test but fails the horizontal, then it is a function, but not one to one.

Hoped this helped you!

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Help asap !<br><br> -100x - 100 = 0<br> -100x = ?<br> x = ?
marin [14]

Answer:

-100x = 10 x = 1

Step-by-step explanation:

I did the math and this is what I got

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3 years ago
The coordinates of the vertices of a right triangle are (0, 0), (5, 0) and (0, 3). Which of the following statements is true?
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I think A I'm not sure.
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1/7 + 6/7 equals1/7 + 6/7 equals
Ivanshal [37]

Answer:

7/7 = 1

Step-by-step explanation:

1/7 is one out of seven part plus 6/7 which is 6 out of seven parts. The denominator does not need to change because it is a common denominator. Just simply add the numerators, 1 and 6 and you get 7. The numerator is divided by the denominator (7/7) which equals to 1.

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A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

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Cole said All prime numbers are odd and all composite numbers are even do you agree with cole?
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A prime number is such that it is divisible by only itself and one. ... Two is a prime because it is divisible by only two and one. All the other even numbers are not prime because they are all divisible by two. That leaves only the odd numbers.
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