What is the sum of the arithmetic sequence 6, 14, 22,
if there are 26 terms
1 answer:
Sum of nth term of arithmetic sequence is given by Sn = n/2[2a + (n - 1)d] Here, a = 6, n = 26 and d = 14 - 6 = 8 S26 = 26/2[2(6) + (26 - 1)8] = 13[12 + 25(8)] = 2,756
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