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eimsori [14]
3 years ago
12

What is the sum of the arithmetic sequence 6, 14, 22, if there are 26 terms

Mathematics
1 answer:
Arisa [49]3 years ago
3 0
Sum of nth term of arithmetic sequence is given by Sn = n/2[2a + (n - 1)d]
Here, a = 6, n = 26 and d = 14 - 6 = 8
S26 = 26/2[2(6) + (26 - 1)8] = 13[12 + 25(8)] = 2,756
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Please please help, need this done by 1:45!!!!
GarryVolchara [31]

Answer:

option B. MB/AM=NC/AN

Step-by-step explanation:

we know that

The <u><em>Triangle Proportionality Theorem</em></u> states that if a line is parallel to one side of a triangle and it intersects the other two sides, then it divides those sides proportionally

In this problem

MN is parallel to BC

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7 0
3 years ago
Ok ong i'm struggling and need help i've been up all night- Ill give brainlyest!!
Ipatiy [6.2K]

Answer:

  1. 1
  2. - 9
  3. 13
  4. 15

Step-by-step explanation

- 7(6x-1)+x=36

  1. => 42x - 7 + x = 36
  2. => 43x - 7 = 36
  3. => 43x =  36 + 6 = 43
  4. => x = 43 / 43 = 1

- 11-2(8+3p)=7²

  1. => 11 - 16 - 6p = 7^2
  2. => 11 - 16 - 6p = 49
  3. => -5 - 6p = 49
  4. => -6p = 49 + 5 = 54
  5. => p = (54) / (-6) = - 9

-  1/4(5b+11)=19

  1. => (5/4)b +  (11/4) = 19
  2. => (5/4)b = 19 - (11/4) = 65 /4
  3. => b = (65/4) / (5/4) => (65/4) * (4/5) = 13

- 2/7(4m-18)=12

  1. => (8/7)m - (36/7) = 12
  2. => (8/7)m = 12 + (36/7) = 120/7
  3. => m = (120/7) / (8/7) = 120 /8 = 15

3 0
3 years ago
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