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2 years ago

Find the square of the radical expression of 121

Mathematics

1 answer:

Alinara [238K]2 years ago

6 0

It 11 because the square root of 121 is 11

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Solving 8 problems per minute, Fast Finn can finish his test in time. He was however, working faster, solving 10 problems per mi

mrs_skeptik [129]

Answer:

Number of problems = 240

Step-by-step explanation:

Let x be the number of questions and t be the time.

Given:

Average rate = 8 problems per minute

Fast Finn rate = 10 problems per minute

Fast Finn taken time = t - 6

We need to find the number of problems on the test paper.

Solution:

Average rate to solve test paper.

$Average\ rate =\frac{Number\ of\ questions}{time}$

$8 =\frac{x}{t}$

$t =\frac{x}{8}$ --------------(1)

Fast Finn rate to solve the test paper.

$Average\ rate =\frac{Number\ of\ questions}{time}$

$10 =\frac{x}{t-6}$

Using cross multiplication rule.

$x=10(t-6)$

$x=10t-60$

substitute $t =\frac{x}{8}$ from equation 1.

$x=10(\frac{x}{8}) -60$

Rearrange the equation as:

$x - \frac{5}{4}x = -60$

$\frac{4x-5x}{4}=-60$

$-\frac{x}{4} = -60$

Using cross multiplication rule.

$x = 60\times 4$

x = 240 problems.

Therefore, 240 problems were on the test.

4 0

2 years ago

4. Suppose Tyler sprayed around the house for ants. Which formula would be used to find the number of ants still alive after a c

babunello [35]

Answer:

I think that the answer is A.

Step-by-step explanation:

6 0

2 years ago

The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(

SVEN [57.7K]

d = 3 , a₁₂ = 40 and S $x_{100}$ = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• a $n$ = a₁ + (n-1)d</h3><h3>• S $_n$ = $\frac{n}{2}$ [2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = $\frac{50}{2}$ [(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>