Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell
(2.5 m/s) x (45 s) = 112.5 meters .
If it wound up only 40 meters underwater, then it must have fallen
(112.5 m - 40 m) = 72.5 meters
from its storage position on the big cruise ship,
before it ever reached the water.
Since it was falling at the rate of 2.5 m/s, it took
(72.5 m) / (2.5 m/s) = 29 seconds
to get down to the water surface after it started dropping.
I put .2 into a fraction and i got 5 17/40. 2/10 equals to 1/5 and 5/8 and 1/5 LCD is 40. I subtracted them and got 5 17/40.
