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sladkih [1.3K]
3 years ago
13

Solve for 12 - 3/4(d+16 )=-5

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0
Solved for d: d=20/3
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5x + 3 = 23 5. 4 = 3a – 14 6. 2y + 5 = 19 i need help with this equation
mrs_skeptik [129]

Answer:

Step-by-step explanation:

    5x + 3 = 23 x=4

5. 4 = 3a – 14 a=6

6. 2y + 5 = 19 y=7

6 0
3 years ago
4(x+5) = 4x +5x it's probably easy but i'm dumb
Irina18 [472]
<span>4(x+5) = 4x +5x

Simplify by distributing and combining like terms
</span>(4)(x)+(4)(5)=4x+5x
4x+20=4x+5x
4x+20=(4x+5x)
4x+20=9x

Subtract 9x from each side
4x+20−9x=9x−9x
5x+20=0
<span />
Subtract 20 from each side
−5x+20−20=0−20
−5x=−20

Divide each side by -5
-5x ÷ -5 = -20 ÷ -5
x = 4

P.S this was actually harder than most algebra problems, so don't beat yourself about it :D<span /><span /><span /><span /><span />
6 0
3 years ago
Please help please these are short answers
atroni [7]

Answer: The answers are given below.


Step-by-step explanation:  The calculations are as follows:

(19) Weight of the puppy last week is

W_\ell=2\dfrac{1}{2}~\textup{lb},

and weight of the puppy this week is

W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.

Therefore, the weight gained by the puppy is given by

W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

H_\ell=\dfrac{4}{9}~\textup{hr},

and the time taken by Nazia to complete her Mathematics homework is

H_m=\dfrac{2}{9}~\textup{hr}.

Therefore, Nazia takes more time to complete Language Arts homework, by

H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.

(22) Quantity of Aluminium collected by Maya is

A_m=\dfrac{4}{20}=0.2~\textup{lb},

and the quantity of Aluminium collected by her friend Abigail is

A_a=\dfrac{7}{8}=0.87~\textup{lb}.

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.

(23) Quantity of snow fall last Wednesday is

S_w=3\dfrac{1}{4}=3.25~\textup{in.},

and quantity of snowfall on sunday is

S_s=3\dfrac{4}{5}=3.8~\textup{in.}.

Therefore, quantity of snowfall was more on Sunday by

S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.

Thus, all the questions are answered.

3 0
3 years ago
what is the slope intercept form of the equation of the line described by (-4,-5), parallel to y=-2x -5
Eddi Din [679]

Answer:

y = - 2x - 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x - 5 ← is in slope- intercept form

with m = - 2, thus

y = - 2x + c ← is the partial equation of the line

To find c substitute (- 4, - 5) into the partial equation

- 5 = 8 + c ⇒ c = - 5 - 8 = - 13

y = - 2x - 13 ← equation of line

7 0
3 years ago
PLEASE HELP....
astraxan [27]

Answer:

Step-by-step explanation:

If you treat 90° as 1 unit on the graph, then

P(1,0) corresponds to (0,0) and (360,0) on the sin graph (say (0,0) though)

P(0,1) corresponds to (90,1) on the sin graph

P(-1,0) corresponds to (180,0) on the sin graph

P(0,-1) corresponds to (270,-1) on the sin graph

7 0
3 years ago
Read 2 more answers
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