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Charra [1.4K]
3 years ago
15

Last year, Deshaun had $20,000 to invest. He invested some of it in an account that paid 9% simple interest per year, and he inv

ested the rest in an account that paid 5% simple interest per year. After one year, he received a total of $1440 in interest. How much did he invest in each account?
Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

Answer:

the amount Deshaun invested in an account that paid 9% interest = $9,000

the amount Deshaun invested in an account that paid 5% interest = $11,000

Step-by-step explanation:

Let x = the amount Deshaun invested in an account that paid 9% interest

Let y = the amount Deshaun invested in an account that paid 5% interest.

Thus;

x + y = 20,000 - - - - (eq 1)

Now, After one year, he received a total of $1440 in interest. Thus;

0.09x + 0.05y = 1440

Multiply each term by 100 to give;

9x + 5y = 144000 ---- (eq 2)

Making x the subject in equation 1,we have;

x = 20,000 - y

Putting 20,000 - y for x in eq 2,we have;

9(20,000 - y) + 5y = 1440

180000 - 9y + 5y = 144000

180000 - 4y = 144000

180000 - 144000 = 4y

36000 = 4y

Divide both sides by 4 to give;

y = 36000/4

y = $9,000

x = 20,000 - 9000

x = $11,000

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Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has
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Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0),  Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8  

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

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What is 1231221 ÷ 272727÷0
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??? what type of question is that??
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2 years ago
In my pocket I have 8 quarters and 6 dimes. What fractional portion of the coins in my pocket are dimes
marin [14]

im pretty sure the answer is 3/4

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2 years ago
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Maksim231197 [3]

Answer:

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2 years ago
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Step-by-step explanation:

I assume as "equation" we mean the slope-intercept form :

y = ax + b

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y - y1 = a(x - x1)

where "a" is again the slope, and (x1, y1) is a point on the line

y - -6 = -10/17 × (x - -9)

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y = -10/17 × x - 90/17 - 6 =

= -10/17 × x - 90/17 - 102/17 =

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so, the equation is (in a maybe nicer way)

y = -1/17 × (10x + 192)

7 0
1 year ago
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