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Damm [24]
3 years ago
13

A line includes the two points 9,-11 and 15,-11 what is its equation in slope intercept form

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0
9 -11 was a terrible tragedy
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the first term of an arthimetic sequence is 42 the rule an= an-1 +8 can 1 can be used explain how to write explict rules
Svet_ta [14]

Answer:

34 + 8n

Step-by-step explanation:

a₁ = 42

a_{n} = a_{n-1} + 8

a₂ = a₁ + 8    = 42 + 8   = 50

a₃ = a₂ + 8   = 50 + 8 = 58

a₄ = a₃ + 8 =   58 + 8  = 66

Arithmetic sequence: 42, 50 , 58 , 66, ......

a₁ = 42 ; d = 8

a_{n} = a₁ + d(n-1)

    = 42 + 8(n - 1)

    = 42 + 8n - 8

   = 34 + 8n

3 0
3 years ago
Read 2 more answers
HELPPPPP PLEASEEEEE!!!
Pepsi [2]

Answer:

The height of right circular cone is h = 15.416 cm

Step-by-step explanation:

The formula used to calculate lateral surface area of right circular cone is: s=\pi r\sqrt{r^2+h^2}

where r is radius and h is height.

We are given:

Lateral surface area s = 236.64 cm²

Radius r = 4.75 cm

We need to find height of right circular cone.

Putting values in the formula and finding height:

s=\pi r\sqrt{r^2+h^2}\\236.64=3.14(4.75)\sqrt{(3.75)^2+h^2} \\236.64=14.915\sqrt{(3.75)^2+h^2} \\\frac{236.64}{14.915}=\sqrt{14.0625+h^2}  \\15.866=\sqrt{14.0625+h^2} \\Switching\:sides\:\\\sqrt{14.0625+h^2} =15.866\\Taking\:square\:on\:both\:sides\\(\sqrt{14.0625+h^2})^2 =(15.866)^2\\14.0625+h^2=251.729\\h^2=251.729-14.0625\\h^2=237.6665\\Taking\:square\:root\:on\:both\:sides\\\sqrt{h^2}=\sqrt{237.6665} \\h=15.416

So, the height of right circular cone is h = 15.416 cm

4 0
3 years ago
The functions q and r are defined as follows.
Bad White [126]

Answer:

9x = 1-1 is q     r x= 2x2 + 2 is 4

5 0
3 years ago
What is the GCF of 12 and 7
madam [21]

Answer:

The GCF of 7 and 12 is 1.

8 0
4 years ago
Read 2 more answers
An arithmetic sequence with a third term of 8 and a constant difference of 5
Vanyuwa [196]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ \hrulefill\\[0.5em] a_3=8\\ n=3\\ d=5 \end{cases} \\\\\\ a_3=a_1+(3-1)5\implies 8=a_1+(2)5 \\\\\\ 8=a_1+10\implies -2=a_1 \\\\\\ \begin{cases} a_1=-2\\ d=5 \end{cases}\implies a_n=-2+(n-1)d

5 0
3 years ago
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