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son4ous [18]
2 years ago
14

What is the slope of the linear function above? Write any fractions as improper fractions, using a '/'. (PLEASE HELP ME)

Mathematics
2 answers:
aliina [53]2 years ago
8 0
-3/2
Down 3
Right 2
As an improper fraction it would be -1 1/2
gizmo_the_mogwai [7]2 years ago
6 0

Answer:

-3/2

Step-by-step explanation:

So you would want start from the point and count up which is the rise. Then count either left or right depending which side the line is on the graph. For this graph it's left. For the problem you would count up to three and move to the left 2 times.

rise over run

-3/2

Hope this makes sense!

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PLS HELP I WILL DO ANYTHING
Lunna [17]

Answer:

the solution for x is x=40

4 0
3 years ago
Paul wants a bike that cost $400. If he had saved 60% of this amount, how much had he saved.
enyata [817]
Hey!


To solve this problem, we'll first start by creating an equation.

<em>Our Created Equation :
</em>
\frac{400 x 60}{100}

Now we'll solve it step by step to find the answer.

So we should begin by multiplying the to portion of our fraction.

<em>400 x 60 = 24,000</em>

Next, we divide our answer by 100, since that is the next step to our equation.

<em>24,000 ÷ 100 = 240</em>

So, our answer is...

<em>Paul has already saved</em>  $240.00  <em>of the $400.00 he must pay for a new bike.</em>

Hope this helps!


- Lindsey Frazier ♥
4 0
3 years ago
Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6
Anton [14]

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

V= \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder,x^{2}+y^{2} =1 and the ellipsoid, 4x^{2}+ 4y^{2} + z^{2} =64

In polar coordinates, we know that

x^{2}+y^{2} =r^{2}

So, the ellipsoid gives

4{(x^{2}+ y^{2)} + z^{2} =64

4(r^{2}) + z^{2} = 64

z^{2} = 64- 4(r^{2})

z=± \sqrt{64-4r^{2} }

So, the volume of the solid is given by:

V= \int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta

= 2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta

To solve the integral take, 64-4r^{2} = t

dt= -8rdr

rdr = \frac{-1}{8} dt

So, the integral  \int\ r\sqrt{64-4r^{2} } rdr become

=\int\ \sqrt{t } \frac{-1}{8} dt

= \frac{-1}{12} t^{3/2}

=\frac{-1}{12} (64-4r^{2}) ^{3/2}

so on applying the limit, the volume becomes

V= 2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta

=\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta

V = \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Since, further the integral isn't having any term of \theta.

we will end here.

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

#SPJ4

3 0
1 year ago
The speeders soccer team charged $12 to wash each car at a fundraiser car wash.The team collected a total os $672 by the end of
sukhopar [10]

They washed 56 cars because 672/12=56

4 0
3 years ago
Read 2 more answers
Eric earned $100 in tips on Sunday waiting tables plus an additional $11.50 per hour. He earned at least $250 in all.
snow_tiger [21]

Answer:

13

Step-by-step explanation:

So first Subtract 100 from 250. Since you are trying to find out the amount of hours, you don’t need the tips to count.

The next step is too either do the equation 150 divided by 11.50 or you can multiply 11.50 by 13.

it’s not fourteen because 149.5 is closer to 150 then 161

Hope this helps

7 0
2 years ago
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