To show that they used the same amount of ribbon you could take the 1 yard and divided into different sized equal groups.
1 yard divided by four equals 1/4 yard for each of four ribbons.
1 yard divided by six equals 1/6 yard for each of six ribbons.
You could have ribbons the size of 1/4 our yard and 1/6 yard, but you would have different amounts of each.
I would say b but i’m not 100% sure lol
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
12/4
Step-by-step explanation:
4/4 is 1
1/4 is well 1/4
2 2/4 is 2 1/2
12/4 is 3
the greatest fraction is 3
Answer:
Step-by-step explanation:
we know that
The probability that it will hit a point in the outer (yellow) ring is equal to divide the area of the yellow ring by the total area of the target
step 1
Find the area of the yellow ring
![A=\pi [7^{2} -5^{2}]](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5B7%5E%7B2%7D%20-5%5E%7B2%7D%5D)
step 2
Find the total area of the target
![A=\pi [7^{2}]](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5B7%5E%7B2%7D%5D)
step 3
Find the probability
Convert to percentage
