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3 years ago

What is that in scientific notation.

Mathematics

2 answers:

Verizon [17]3 years ago

4 0

I think it just wants you to leave it in standard form to be honest. the final answer is just 3.5x10^-1

ASHA 777 [7]3 years ago

3 0

The answer is 3.5 x 10^ -2. you have to use distribution

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Hayden and his friends want to draw a court on the playground to play four square . The sides of each of the small square are 4

aksik [14]

Answer:

Step-by-step explanation:

let me know if that was correct

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3 years ago

What is the equation of the line through the points (3,2), (8,5), (13,8), and (18,11)

olga_2 [115]

For this question the answer is the second one

4 0

3 years ago

Help!!!!!! algebra 1

Vinil7 [7]

Answer:

f(8) = 195

Step-by-step explanation:

When the x if f(x) is replaced with an 8, this just means that it is the eighth term. All you really have to do is replace every X in the function to find the answer.

f(8) = 3 + 3(8)²

f(8) = 3 + 3(64)

f(8) = 3 + 192

f(8) = 195

Hope this helps!

5 0

3 years ago

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enyata [817]

Answer:

is that 12.75 or 2.75

Step-by-step explanation:

4 0

4 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

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Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

5 0

3 years ago