Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
What part do you have trouble with
If this an angle on a straight line the answer is k=73°
Hello!
The left triangle have two same side length so the two bottom angles are the same which is (180-56)/2=62
See the left triangle bottom right angle and the right triangle bigger angle have the sum of 180 degree so the bigger angle=180-62=118
The right triangle also have two same sides so they also have same angle degree so x=(180-118)/2=31
Have a great day!
Answer:
the answer is 8
Step-by-step explanation:
9 - 8 = 1
- Hope this helps
- Brainliest plz