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marin [14]
3 years ago
9

Solve the system using elimination. 2x + 18y = -9 4x + 18y = -27

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

First, let's cancel out the x by multiplying 2x + 18y = -9 by -2.

-2 ( 2x + 18y = -9) = -4x -36y = 18

Then, we combine the two equations.

-4x + 4x = 0

18y - 36y = -18y

-27 + 18 = -9

Our new equation is -18y = -9.

Now, divide both sides by -18.

-18y / -18 = y

-9/ -18 = 1/2

y = 1/2

We can plug in a value for y since y = 1/2 now.

Let's use 2x + 18y = -9

Plug in y.

2x + 18(1/2) = -9

2x + 9 = -9

Then, subtract 9 from both sides.

2x = -18

Divide by 2.

2x/2 = x

-18/2 = -9

x = -9

Lastly, we can plug in both x and y values to see it works.

2(-9) + 18(1/2) = -9

-18 + 9 = -9

Therefore, the values of x and y does work.

x = -9

y = 1/2

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Step-by-step explanation:

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b)   3x - 2y = 10 + 4x   ... subtract 3x on both sides

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       y = -5 - 0.5x ... move -0.5 to the left so it matches y = mx + b

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In the transformation ABC A'B'C', the preimage of B' is ____. . a0
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Step-by-step explanation:

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How do you solve f(x) = x2 + x - 20?​
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\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + 5x - 4x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x(x + 5) - 4(x + 5)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(x + 5)(x -  4)

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x =  - 5 \:  \: and \:  \: 4

4 0
2 years ago
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