Answer:
The standard deviation of the following data set is 32.2
Step-by-step explanation:
step 1
Find the mean
we have
![[56,78,123,34,67,9,20]](https://tex.z-dn.net/?f=%5B56%2C78%2C123%2C34%2C67%2C9%2C20%5D)
Sum the data and divided by the number of elements
![[56+78+123+34+67+91+20]/7=469/7=67](https://tex.z-dn.net/?f=%5B56%2B78%2B123%2B34%2B67%2B91%2B20%5D%2F7%3D469%2F7%3D67)
step 2
For each number: subtract the Mean and square the result
![[(56-67)^{2},(78-67)^{2},(123-67)^{2},(34-67)^{2},(67-67)^{2},(91-67)^{2},(20-67)^{2}]](https://tex.z-dn.net/?f=%5B%2856-67%29%5E%7B2%7D%2C%2878-67%29%5E%7B2%7D%2C%28123-67%29%5E%7B2%7D%2C%2834-67%29%5E%7B2%7D%2C%2867-67%29%5E%7B2%7D%2C%2891-67%29%5E%7B2%7D%2C%2820-67%29%5E%7B2%7D%5D)
![[121,121,3,136,1,089,0,576,2,209]](https://tex.z-dn.net/?f=%5B121%2C121%2C3%2C136%2C1%2C089%2C0%2C576%2C2%2C209%5D)
step 3
Work out the mean of those squared differences
This value is called the "Variance"
step 4
Take the square root of the variance
Answer:
68°
Step-by-step explanation:
ABD is a right angle and the measure of it is 90°
m<CBD + m<ABC = m<ABD
4x + 52° + 8x - 10 = 90° add like terms
12x + 42° = 90°
12x = 48°
x = 4
m<CBD is 4x + 52° replace x with 4
4×4 + 52 = 68°
Yess, such fun so
q=number of quarter
n=number of nickles
q+n=63
9.15=915 cents
25 cents=1 q
5 cents=1 n so
915=25q+5n
915=5(5q+n)
divide by 5
183=5q+n
we also have q+n=63
subtract q from both sides
n=63-q
subsitute 63-q for n in second equation
183=5q+63-q
add like terms
183=4q+63
subtract 63 from both sides
120=4q
divdie by 4
30=q
there were 30 quarters
subsitute
63=30+n
subtract 30
33=n
30 quarters
33 nicles
Hi,
I assume the forward slash meant it as a fraction VS it being a division symbol. To answer your question, the remainder is 10.
Hope this helps.