Answer:
7.6 seconds
Step-by-step explanation:
To solve this problem we can use the following equation:
S = So + 113*t + at^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
In this problem, we have that S = 0, So = 65, Vo = 113 and a = -32 ft/s2 (The acceleration of gravity)
So we have that:
0 = 65 + 113t - 16t2
16t2 - 113t - 65 = 0
Using Bhaskara's formula, we have:
Delta = 113^2 + 4*65*16 = 16929
sqrt(Delta) = 130.11
t = (113 + 130.11) / (2*16) = 7.597 seconds
Rounding to nearest tenth, we have t = 7.6 seconds
Answer:
When raising a power to a power in an exponential expression, you find the new power by multiplying the two powers together. For example, in the following expression, x to the power of 3 is being raised to the power of 6, and so you would multiply 3 and 6 to find the new power.
Step-by-step explanation:
Answer:
0
Step-by-step explanation:Velocity at t= 0s is 20m/s and the velocity at t= 10s is 20m/s.
a= 20-20/ 10s
a=0m/s
The flow rate is 2 quarts per minute. There are 4 quarts in a US gallon, so 2 quarts divide 4 quarts per US gallon = 0.5 gallons per minute There are 60 seconds in a minute, so the flow rate is 0.5 gallons per minute divide 60 seconds per minute = 0.0083 gallons per second
