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Irina18 [472]
3 years ago
7

Deshawn has two bags of marbles. The first bag has 2 blue, 3 orange, and 5 red. The second bag has 4 pink, 10 blue, and 6 brown.

If he pulls a marble out of each bag, what is the probability that he will pull out a blue marble from each bag
Mathematics
1 answer:
madreJ [45]3 years ago
3 0

Answer: 0.1

Step-by-step explanation:

Given

Bag-I has 2 blue,3 orange, 5 red

Bag-II has 4 Pink,10 blue, 6 brown

No of ways of choosing a blue marble from bag-I

\Rightarrow ^2C_1

Total no of ways of choosing a marble from bag-I

\Rightarrow ^{10}C_1

No of ways of choosing a blue marble from bag-II

\Rightarrow ^{10}C_1

Total no of ways of choosing a marble from bag-II

\Rightarrow ^{20}C_1

The probability that he will pull out a blue marble from each bag is

\Rightarrow P=\text{Probability of pulling a blue marble from bag-I}\times \text{Probability of pulling a blue out bag-II}

\Rightarrow P=\dfrac{^2C_1}{^{10}C_1}\times \dfrac{^{10}C_1}{^{20}C_1}\\\\\Rightarrow P=\dfrac{2}{10}\times \dfrac{10}{20}=\dfrac{1}{10}

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{9}^{15}

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Bacteria can multiply at an alarming rate when each bacteria splits into two new cells, thus doubling. if we start with only one
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Roughly 16 million bacteria.

Step-by-step explanation:

Multiply the rate of the bacteria going through mitosis times the amount of daughter cells per hour, for this case.

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Hope this helps!

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2 years ago
Two fair dice, one blue and one red, are tossed, and the up face on each die is recorded. Define the following events:
ZanzabumX [31]

Answer:

Step-by-step explanation:

Given that two fair dice, one blue and one red, are tossed, and the up face on each die is recorded.

a) P(E) = P(the difference of the numbers is 3 or more}

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P(E) = \frac{12}{36} =\frac{1}{3}

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3 years ago
Read 2 more answers
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ExtremeBDS [4]

Answer: m=6, m=-4

Step-by-step explanation:

To solve this proportion, we have to cross multiply.

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(m-3)(m+8)=7m

Now that we have cross multiplied, we actually need to FOIL the left side to expand the equation.

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Combine like terms.

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We can move all terms to one side and then solve for m.

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We can actually factor this to:

(m-6)(m+4)=0

We set each factor equal to 0 to find m.

m-6=0

m=6

m+4=0

m=-4

6 0
3 years ago
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