Answer:
a.$7.43 per machine hour
Explanation:
The computation of the single plant wide rate is shown below:
Single plant wide rate = Total overhead cost ÷ Machine hours
where,
Total overhead cost = $84,000 + $72,000 = $156,000
And, the machine hours is
= 1,000 units × 5 + 2,000 units × 8
= 5,000 + 16,000
= 21,000 machine hours
So, the single plant wide rate is
= $156,000 ÷ 21,000 machine hours
= $7.43 per machine hour
I don’t understand this question
Solution:
Given Information,
Heat input is ( ) = 5.5 × Btu/h
Combustion efficiency of the boiler () = 0.7
Combustion efficiency after turn up () = 0.8
Operation Hour (t) = 5200h
Unit cost (c) =
Calculate heat output from the boiler = x
= 5.5 x x 0.7
= 3.85 x Btu/h
Calculate the heat input to the boiler after the tune-up
= /
= 3.85 x / 0.8
= 4.8125 x Btu/h
Calculate the saved energy after the tune-up
= -
= 5.5 x - 4.8125 x Btu/h
= 0.6875 x Btu/h
Calculate the annual energy saving ( )
= x t
= ( 0.6875 x Btu/h ) ( 5200 hr/yr)
= 3575 x Btu/h
Calculate the annual cost saving
Annual cost saving = x Unit cost
= 3575 x Btu/h x
= 82225
Answer:
The annual rate of return is -2.83%
Explanation:
The annual rate can be calculated from the formula FV=PV*(1+r)^N
Where FV is the future value of the investment
PV is the amount invested which is $276,500
N is 9 years
213600=276,500*(1+r)^9
213600/276500=(1+r)^9
divide index on both sides by 9
(213600/276500)^1/9=1+r
(213600/276500)^1/9-1=r
r=-0.02827109
r=-2.83%
Hence the annual rate of return on the investment is -2.83%, which means the investment depleted by 2.83% from initial invested amount of $276,5000 to $213,600 after nine years