JK + KL = JL
JK = 2x, KL = x + 2, JL = 5x - 10
therefore we heve the equation:
2x + (x + 2) = 5x - 10
3x + 2 = 5x - 10 |-2
3x = 5x - 12 |-5x
-2x = -12 |:(-2)
x = 6
JK = 2x → JK = 2(6) = 12
KL = x + 2 → KL = 6 + 2 = 8
JL = 5x - 10 → JL = 5(6) - 10 = 30 - 10 = 20
Check:
JK + KL = JL
12 + 8 = 20 CORRECT :)
Answer:
( -1 , 26)
Step-by-step explanation:
So since you need to find the other endpoint, you would follow these steps:
1.) 
2.) 8 = 9 + x ( you just multiplied the 2 to the 4 to get 8)
3.) -1 = x (just solve it like a regular equation, so just subtract 9 on both sides to get rid of it and that leaves you with -1 = x)
You took the x values of both points and put them in the equation.
And its the same for y
1.) 
2.) 16 = -10 + y
3.) 26 = y (you added the 10 on both sides because the 10 was negative and that took the 10 out and so it left you with 26 = y)
Answer:
C
Step-by-step explanation:
sin C=12/13
cos A=12/13
so sin C=cos A