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katrin [286]
3 years ago
11

The population of Augusta, WI, had a population of 1253 in 2000. If the population increased by 3% each year, what would be the

population of Augusta in 2016?
Mathematics
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

The Population growth function is given by:

A(t) = A_0(1+r)^t

where

A_0 is the initial population.

r is the growth rate (in decimal)

t is the time in year.

As per the statement:

The population of Augusta, WI, had a population of 1253 in 2000.

In 2000

⇒A_0 =1253

It is also given that the population increased by 3% each year

⇒r = 3% = 0.03

then;

A(t) =1253(1+0.03)^t              .....[1]

We have to find the population of Augusta in 2016.

⇒t = 16 years

Substitute the given values in [1] we have;

A(t) =1253(1+0.03)^{16}

⇒A(t) =1253(1.03)^{16}

⇒A(t) =1253 \cdot 1.60470644

Simplify:

A(t) = 2,010.69717

Therefore, the population of Augusta in 2016 is, 2,010.7

dmitriy555 [2]3 years ago
6 0
A=1,253×1.03^(16)
A=2,010.7
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