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lisabon 2012 [21]
3 years ago
7

Point A is at (2, -8) and point C is at (-4, 7).

Mathematics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

(-2, 2)

Step-by-step explanation:

<u>Given:</u>

  • Point A is at (2, -8) and point C is at (-4, 7)

<u>Difference of coordinates:</u>

  • Δx = 2 - (-4) = 6
  • Δy = - 8 - 7 = - 15

<u>The ratio of AB to AC is 2:1. So:</u>

  • AB = 2*AC/3 and BC = AC/3

<u>Then coordinates of point B should be 2/3 from the point A:</u>

  • x = 2- 6*2/3 = 2 - 4 = -2
  • y = - 8 - (-15)*2/3 = -8 + 10 = 2

So point B has coordinates of (-2, 2)

You might be interested in
On a trip to a lake, Kerrie and Shelly rode their bicycles four more than three times as many miles in the afternoon as in the m
Natalija [7]

Answer:

27 miles in the morning and 85 miles in the afternoon.

Explanation:

Let m be the number of miles they rode in the morning.  They rode 4 more than 3 times this many in the afternoon; this gives us the expression

3m+4

to represent the miles ridden in the afternoon.

Together they rode 112 miles; this means we add the morning miles, m, to the afternoon miles, 3m+4, and get 112:

m+3m+4 = 112

Combine like terms:

4m+4 = 112

Subtract 4 from each side:

4m+4-4= 112-4

4m = 108

Divide both sides by 4:

4m/4 = 108/4

m = 27

They rode 27 miles in the morning.

That means in the afternoon, they rode

3m+4 = 3(27)+4 = 81+4 = 85 miles.

5 0
3 years ago
Read 2 more answers
Who had this before if so can I get help
telo118 [61]

2*3+4=10

5+2x2=9

4-3+2=3

4*3+2=14

20-4x3+6=14

16-30/2+11=12

24/6*5=20

15/5+2=5

2+2*9-5=15

12-3+4*2=1

12/3+3*4=16

9-6/3=7

16-3*4=4

36/4/9=1

The last one is yours

6 0
3 years ago
If AB = 10, what is the length of DE?<br><br> 11<br> 3<br> 12<br> 5
Oliga [24]
The answer is 11. Hope this helped.
3 0
3 years ago
Read 2 more answers
Please answer all
vladimir1956 [14]

Step-by-step explanation:

b) y=x+1

table:

_x _|_2x_|_y_|(x, y)|

0     |2(0)  |1     |(0, 1)|

1      | 2(1)  |2    |(1, 2)|

2     | 2(2) |3    |(2, 3)|

3     | 2(3) |4    |(3, 4)|

c) y=3x+2

_x _|_2x_|_y_|(x, y)|

0     |2(0)  |2     |(0, 2)|

1      | 2(1)  |5    |(1, 5)|

2     | 2(2) |8    |(2, 8)|

3     | 2(3) |14   |(3, 14)|

To graph, plot the x, y points and connect all of them

7 0
3 years ago
B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,
Nadusha1986 [10]

Answer:

\huge{ \fbox{ \sf{Rs \: 40000}}}

Step-by-step explanation:

\sf{Let \: CP \: ( \: cost \: price) \: be \: x}

\sf{Loss \: \% \:  = 5  \% \: }

\sf{Selling \: price = CP \:  -  \: loss \: \% \: of \: CP}

\mapsto{ \sf  x -  \frac{5}{100}  \times x}

\mapsto{ \sf{x -  \frac{x}{20} }}

\mapsto{ \sf{  \frac{x \times 20 - x}{20} }}

\mapsto{ \sf{ \frac{20x - x}{20}}}

\mapsto{ \sf{ \frac{19x}{20}}}

Now, Finding the New selling price

\sf{New \: SP \: ( \: selling \: price)} =  \frac{19x}{20}  + 5200

\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}

\mapsto{ \sf{ \frac{19x + 10400}{20}}}

Finally, finding the Cost price :

We have, Profit % = 8 %

\sf{Cost \: price = Selling \: price \:  -  \: P\% \: of \: CP}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  - 8\% \: of \: x}}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{8x}{100} }}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{2x}{25} }}

\mapsto{ \sf{x =  \frac{5(19x + 104000) - 2x \times 4}{100} }}

\mapsto{ \sf{x =  \frac{95x + 520000 - 8x}{100} }}

\mapsto{ \sf{x =  \frac{87x + 520000}{100}}}

\mapsto{ \sf{100x = 87x + 520000}} \:  \: ( \sf{Cross \: multiplication}

\mapsto{ \sf{100x - 87x = 520000}}

\mapsto{ \sf{13x = 520000}}

\mapsto{ \sf{x =  \frac{520000}{13}}}

\mapsto{ \boxed {\sf{x = 40000}}}

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

5 0
3 years ago
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