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rosijanka [135]
2 years ago
10

What is the surface area of the cylinder

Mathematics
1 answer:
Hitman42 [59]2 years ago
5 0

Answer:

In terms of pi: 164.5pi cm squared

Substituting pi for 3.14: 516.53 cm squared

Step-by-step explanation:

3.5^2 = 12.25pi

12.25*2 = 24.5pi

7pi*20 = 140pi

140 + 24.5 = 164.5pi

164.5*3.14 = 516.53

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A baseball player throws a ball from second base to home plate. How far does the player throw the ball?
Fynjy0 [20]

Answer:

The player throws 127.3 ft from second base to home plate.

Step-by-step explanation:

Given:

Distance from home to first base = 90 ft

Distance from first base to second base = 90 ft

We need to find the distance from second base to home.

Solution:

Now we can assume the complete scenario to be formed as a right angled triangle with two sides given and to find the third side.

Now by using Pythagoras theorem which states that;

Square of the hypotenuse side is equal to sum of squares of other two sides.

framing in equation form we get;

distance from second base to home = \sqrt{90^2+90^2}= 127.27 \ ft

Rounding to nearest tent we get;

distance from second base to home = 127.3 ft

Hence The player throws 127.3 ft from second base to home plate.

6 0
3 years ago
Can anyone help me with this​
ss7ja [257]

Answer:

h

Step-by-step explanation:

h

5 0
3 years ago
If its 5 cookies for every 4 friends how many does each friend have?
Firlakuza [10]

Answer:1.24

Step-by-step explanation

7 0
3 years ago
Read 2 more answers
Use intercepts to graph -7x-2y=-21
NISA [10]

Answer: -7/2

Step-by-step explanation:

8 0
3 years ago
Find the interquartile range (IQR) of the data in the dot plot below. chocolate chips 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10
Brums [2.3K]

*The dot plot is shown in the attachment below

Answer:

2

Step-by-step explanation:

Interquartile range is the difference between the upper median (Q3) and the lower median (Q1).

First, let's write out each value given in the data. Each dot represents a data point.

We have:

2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7

=>Find the median:

Our median is the middle value. The middle value is the 6th value = 4

==>Upper median Q3) = the middle value of the set of data we have from the median to our far right.

2, 3, 3, 4, 4, |4,| 4, 5, [5], 6, 7

Our upper median = 5

==>Lower median(Q1) = the middle value of the data set we have from our median to our far left.

2, 3, [3], 4, 4, |4,| 4, 5, 5, 6, 7

Lower median = 3

==>Interquartile range = Q3 - Q1 = 5-3 = 2

3 0
4 years ago
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