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Ratling [72]
3 years ago
5

Determine algebraically whether the function is even, odd, or neither even nor odd. (2 points)

Mathematics
2 answers:
pentagon [3]3 years ago
5 0

Answer:

The function f(x) is neither even nor odd.

Step-by-step explanation:

The given function is

f(x) = -3x^4 - 2x - 5

A function is called an even function if

f(-x) = f(x)

A function is called an odd function if

f(-x) = -f(x)

Substitute x=-x in the given function, to check whether the function is even, odd, or neither even nor odd.

f(-x) = -3(-x)^4 - 2(-x) - 5

f(-x) = -3(x)^4 + 2(x) - 5

f(-x) \neq f(x)

f(-x) \neq -f(x)

Therefore the function f(x) is neither even nor odd.

ahrayia [7]3 years ago
3 0

Answer:

f(x) is neither odd nor even function

Step-by-step explanation:

we are given

f(x)=-3x^4-2x-5

Firstly, we will find f(-x)

we can replace x as -x

we get

f(-x)=-3(-x)^4-2(-x)-5

now, we can simplify it

f(-x)=-3x^4+2x-5

we can see that

it is neither equal to f(x) nor -f(x)

we know that

For even:

f(-x)=f(x)

For odd:

f(-x)=-f(x)

so, f(x) is neither odd nor even function

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Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.
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The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

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Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

brainly.com/question/938117

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Read 2 more answers
HELP pls!!
Rudiy27
<h3>Answer: Choice B) x = 65, y = 10</h3>

====================================================

Work Shown:

The upper pair of angles 60 degrees and (2x-y) degrees are supplementary angles. This is because of the parallel lines. Note how they are same side interior angles. Therefore, (2x-y) and 60 combine to 180 degrees like so

(2x-y)+60 = 180

2x-y = 180-60 ... subtract 60 from both sides

2x-y = 120 ... call this equation 1

-------

Similarly, (2x+y) and 40 also combine to 180

(2x+y) + 40 = 180

2x+y = 180-40 ... subtract 40 from both sides

2x+y = 140 ... call this equation 2

------

Line up equation 1 and equation 2. Then add straight down

\ \ \  2x-y = 120\\+ 2x+y = 140\\\hrule\\\\\\ \ \ \ 4x+0y = 260\\\\

That becomes 4x = 260 which solves to x = 65 when you divide both sides by 4.

------

If x = 65, then,

2x-y = 120

2(65)-y = 120

130 - y = 120

-y = 120-130

-y = -10

y = 10

or

2x+y = 140

2(65)+y = 140

130+y = 140

y = 140-130

y = 10

----------

Either way end up with x = 65 and y = 10

4 0
3 years ago
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