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FIRST TO ANSWER GETS BRAINLIEST!

Andreyy89

Answer:

I believe it's the first option, but if not ion know

6 0

2 years ago

Read 2 more answers

Find the error in the following sample of work, if one exists.

ch4aika [34]

Answer:

D. There is no mistake.

Step-by-step explanation:

The following lines show the process of factorization by using common factor.

Line 1:

In line 1, the equation is given and is completely fine.

$y^{2}+8xy+2y+16x=0$

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.

Line 2:

In line 2, the terms are grouped, from which we can factor out common terms.

$(y^{2}+8xy)+(2y+16x)=0$

This is also fine.

Line 3:

In line 3, the common term y is taken out from group 1 and 2 from other group.

$y(y+8x)+2(y+8x)=0$

which is exactly what is given in line 3.

Line 4:

In line 4 the common factors can be seen and easily split into 2 factors.

$(y+2)(y+8x)=0$

which is exactly what is given in line 4.

Options:

A. The grouping is correct in line 2. So this option is does not hold.

B. Common factor was factored correctly from group 1. So this option does not hold.

C. Common factor was factored correctly from group 2. So this option does not hold.

D. There is no mistake. This is correct. Thus we choose this option as correct answer.

3 0

2 years ago

How do you mark brainiest answer?

Hoochie [10]

Answer:

there's a blue crown that shows up when either 2 people already answered or if it's been a few days since only 1 person answered, just click that

Step-by-step explanation:

idk if u know this but apparently u gain points for marking someone brainliest, i read that somewhere but i could be wrong

8 0

2 years ago

For which function and interval can the extreme value theorem be applied?

Lana71 [14]

Answer:

A

Step-by-step explanation:

5 0

2 years ago

When given a raw score, explain how to use the normal curve to compare that

stepladder [879]

First of all, you need to come to an understanding of what you mean by "compare that score to the population." Often, that will mean determining the percentile rank of the score.

To determine the percentile rank of a raw score, you first nomalize it by determining the number of standard deviations it lies from the mean. That is, you subtract the population mean and divide that difference by the population standard deviation. Now, you have what is referred to as a "z-score".

Using a table of standard normal probability functions (or an equivalent calculator or app), you look up the cumulative distribution value corresponding to the z-score you have. This number between 0 and 1 (0% and 100%) will be the percentile rank of the score, the fraction of the population that has raw scores below the raw score you started with.

7 0

2 years ago