Answer:
Step-by-step explanation:
4) d = 12 cm; r = 12/2 = 6cm ; h = 5 cm
S.A = 2πr(r + h)
= 2* 3.14 * 6 * (6 + 5)
= 2 * 3.14 * 6 *11
= 414.48 cm²
5) d = 8 cm ; r = 8/2 = 4cm ; h = 7cm
S.A = 2πr(r + h)
= 2 *3.14 * 4 * (4 + 7)
= 2 * 3.14 * 4 * 11
= 276.32 cm²
6) r = 4 cm ; h = 6cm
SA = 2πr(r +h)
= 2 * 3.14 * 4 * 10
= 251.2 cm²
7) Area of front and back = 
= base * height
SA = (front and back) + Base + left + right
= 4* 3 + (8*3) + (8*4) + ( 8*5)
= 12 + 24 + 32 + 40
= 108 cm²
8) SA = (front and back) + Base + left + right
= (8 * 6) + (12*6) + (12*8) + (12*10)
= 48 + 72 + 96 + 120
= 336 cm²
9) SA = (front and back) + Base + left + right
= (12 *5) + (8*5) + (8*12) +(8*13)
= 60 + 40 + 96 + 104
= 300 cm²
Answer:
Step-by-step explanation:
Given
Required
Which of the points does it pass through
To do this, we simply substitute the values of x and y in the above equation.
So, we have:
Solve each bracket
The above equation is true,
<em>Hence, it passed through </em>
)
<em>We do not need to check for others</em>
The equation of the circle is may be expressed as,
(x - h)² + (y - k)² = r²
where h and k are the abscissa and ordinates of its center, respectively, and r is radius. Substituting the given values to the equation above,
(x - 5)² + (y - 3)² = 4²
Simplifying further the equation gives,
x² + y² - 10x - 6y + 18
Answer:
It's point W!!!
Step-by-step explanation:
Have a great day :)
Answer:
Step-by-step explanation:
We are given that
We have to complete the recursive formula of f(n).
Substitute n=1
It forms geometric sequence because the ratio of two consecutive terms are equal.
Therefore, the recursive formula
