Not necessarily.

and

may be linearly dependent, so that their span forms a subspace of

that does not contain every vector in

.
For example, we could have

and

. Any vector

of the form

, where

, is impossible to obtain as a linear combination of these

and

, since

unless

and

.
Answer:
Step-by-step explanation:
In the equation y=kx+1, k is the slope and 1 is the y-intercept.
To find the slope, use the formula k=y2-y1/x2-x1. To use this formula, you need two points. The first point, point M, is given to you. The second point can be the y-intercept, point (0, 1). Now, apply the formula to find the slope: k=3-1/1-0
k=2/1
k=2
We now have the equation y=2x+1.
The next step is to graph the line.
First, graph the y-intercept. Should look something like this: (star represents point. the point is on (0, 1).)
|
|
*
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|
|
Then, use the slope to find your second point: (the point is on (1, 3)).
| *
|
*
------------------------------
|
|
Draw a line through those two points and you have your answer!
Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,


which is a cubic polynomial in
with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).
Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.
f'(x) = 3x² - 1 = 0 ⇒ x = ±1/√3
So, we have three subsets over which f(x) can be considered invertible.
• (-∞, -1/√3)
• (-1/√3, 1/√3)
• (1/√3, ∞)
By the inverse function theorem,

where f(a) = b.
Solve f(x) = 2 for x :
x³ - x + 2 = 2
x³ - x = 0
x (x² - 1) = 0
x (x - 1) (x + 1) = 0
x = 0 or x = 1 or x = -1
Then
can be one of
• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);
• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or
• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)
Answer:
i can;t copy or paste either bro
Step-by-step explanation:
Answer:
4 , 1 and 6
Step-by-step explanation:
now ur not in trouble :)