Answer: E. All of the above statements are true
Step-by-step explanation:
The mean of sampling distribution of the mean is simply the population mean from which scores were being sampled. This implies that when population has a mean μ, it follows that mean of sampling distribution of mean will also be μ.
It should also be noted that the distribution's shape is symmetric and normal and there are no outliers from its overall pattern.
The statements about the sampling distribution of the sample mean, x-bar that are true include:
• The sampling distribution is normal regardless of the shape of the population distribution, as long as the sample size, n, is large enough.
• The sampling distribution is normal regardless of the sample size, as long as the population distribution is normal. • The sampling distribution's mean is the same as the population mean.
• The sampling distribution's standard deviation is smaller than the population standard deviation.
Therefore, option E is the correct answer as all the options are true.
Answer:
Since the null hypothesis is true, finding the significance is a type I error.
The probability of the year I error = level of significance = 0.05.
so, the number of tests that will be incorrectly found significant is computed as follow: 0.05 * 100 = 5
Therefore, 5 tests will be incorrectly found significant given that the null hypothesis is true.
The equation is 
<u>Explanation:</u>
We have to first find the mid-point of the segment, the formula for which is
So, the midpoint will be 
= 
It is the point at which the segment will be bisected.
Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula 
The slope is 
= 
Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of is 
To write an equation, substitute the values in y = mx + c
WHere,
y = -1
x = 3
m = 3/2
Solving for c:
Thus, the equation becomes:
Answer:
12? I'm not sure. That's the answer I think?
