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Bogdan [553]
3 years ago
15

Write the equation of a circle with a center at (-2, 3) and a radius of 4.

Mathematics
1 answer:
Ivan3 years ago
5 0

Answer:

The equation of a circle:

(x+2)^2+(y-3)^2 = 16

Step-by-step explanation:

The equation of a circle:

(x-h)^2+(y-k)^2 = r^2

(where the center is known as (h,k) and the radius, known as r).

-Since you already have the center and the radius, use them for the equation of a circle:

Center: (-2,3)

Radius: 4

(x+2)^2+(y-3)^2 = 4^2

After you have the equation of a circle, simplify the radius by the exponent 2 :

(x+2)^2+(y-3)^2 = 16

So, you have found the equation of a circle.

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5-13)<br> -10-15<br> what’s the equation for the line that passes through points (5,-3) and (-10,15)
umka2103 [35]

Answer: y=-6/5x+3

Step-by-step explanation:

To find the equation of the line that passes through the points, you want to first find the slope by using the formula m=\frac{y_2-y_1}{x_2-x_1}, then solve for the y-intercept.

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Now that we have the slope, we can plug in a given point and solve for the y-intercept.

15=-6/5(-10)+b        [multiply]

15=12+b                   [subtract both sides by 12]

b=3

Now that we have the y-intercept, we know the equation is y=-6/5x+3.

7 0
3 years ago
Can someone help me with this
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Step-by-step explanation:

                   

4 0
3 years ago
the room charge for a hotel is 230$ each day. the estevez family spends 4 days on vacation at the hotel . at the end of their st
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hope i helped:)
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3 years ago
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