Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or, 
or, 
or, 
or, 
Substituting the value of in ∠QPR we get,
∠QPR = 
or, ∠QPR = 
Hence,
The value of ∠QPR is 40°.
Answer:
c
Step-by-step explanation:
c appears to be the better description as the line on the left has a solid circle at x = 1 indicating it is defined for x ≤ 1
While the line on the right has an open circle at x = 1 indicating it is defined for x > 1
Both line segments have a negative slope, thus
y = - 2x + 1 x > 1
y = - x + 2 : x ≤ 1
Answer:
<h3>Move all the x terms to one side. Use inverse operations and add 1 5 x 15x 15x to both sides to keep the equation balanced. Solve by working backwards from the order of operations. This means we need to undo the −2 first by adding 2 to both sides of the equation to keep it balanced.</h3>
$41.04 you multiply how long and how wide it is together. after that that the answer is 2,070 then divide it by 50 and you get $41.04.
i hope that helps!!
