She has 52 card all together so she has a probability of drawing on the first draw 4 L's or R's because their are two sets of alphabet cards. So that is 4/52 or 1/13 to the lowest term. Second turn she only has 51 cards to draw from and still has 4 L's and R's so that would be 4/51 and on the third try she has only 50 cards left so that would be 4/50 or 2/25 to the lowest term. Now multiply all three factions 1/13 x 4/51 x 2/25 = 8/16575 meaning out of the three draws she has a probability of getting a L or R, 8 out of 16575 each draw.
Find the mean, median and mode of the given data? 8, 10,11, 8, 14,18, 8, 10, 11, 8, 15
Inessa05 [86]
Answer:
it might be 18 ❤
Step-by-step explanation:
I'm pretty sure it is 18 let me know
The answer will be C. OR 3. 11−<span>13<span>i</span></span>
Answer:
ok
Step-by-step explanation:
There are 2001 items in that set.
So n(A) = 2001
We can individually count them all out, which is very slow and tedious, or we can use the formula
n-m+1
where,
m = starting value
n = ending value
In this case,
m = 0
n = 2000
So,
n-m+1 = 2000-0+1 = 2001
This formula only works if we increase the number by 1 each time (eg: 6, 7, 8, etc)
