Notice that
11/12 = 1/6 + 3/4
so that
tan(11π/12) = tan(π/6 + 3π/4)
Then recalling that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
⇒ tan(x + y) = (tan(x) + tan(y))/(1 - tan(x) tan(y))
it follows that
tan(11π/12) = (tan(π/6) + tan(3π/4))/(1 - tan(π/6) tan(3π/4))
tan(11π/12) = (1/√3 - 1)/(1 + 1/√3)
tan(11π/12) = (1 - √3)/(√3 + 1)
tan(11π/12) = - (√3 - 1)²/((√3 + 1) (√3 - 1))
tan(11π/12) = - (4 - 2√3)/2
tan(11π/12) = - (2 - √3) … … … [A]
Answer: 110°
<u>Step-by-step explanation:</u>
∠A ≅ ∠B
since ∠A = 35° (given), then ∠B = 35°
Use the Triangle Sum Theorem to find ∠C:
∠A + ∠B + ∠Q = 180°
35° + 35° + ∠Q = 180°
70° + ∠Q = 180°
∠Q = 110°
The central angle (∠AQB) ≅ arc AB
since ∠AQB = 110° (solved above), then arc AB = 110°
Y=f(x)=2x find f(x) when x=2
Plug in
f(2)=2(2) =4
Answer
4
11z/16+7z/8=5/16
(11z+14z)/16=5/16
25z=5
z=5/25=1/5
