Suppose the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average
1 answer:
Answer:
0.5372
Step-by-step explanation:
Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.
Let X be the no of births in the hospital per hour
X is Poisson
with mean = 1.8
the probability of observing at least two births in a given hour at the hospital
=
the probability of observing at least two births in a given hour at the hospital = 0.5372
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Answer:
Step-by-step explanation:
You need to remember the Product of powers property:
Then, knowing this property, now you have to apply the Distributive property. So:
Finally, to simplify this expression, you need to add the like terms.
Therefore, you get that the product is:
So we have the system of equations:
equation (1)
equation (2)
To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for
in equation (2):
equation (3)
Replacing equation (3) in equation (1):
equation (4)
Replacing equation (4) in equation (3):
We can conclude that the solution of our system of equations is <span>(7/5, 21/10)</span>
To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for
Replacing equation (3) in equation (1):
Replacing equation (4) in equation (3):
We can conclude that the solution of our system of equations is <span>(7/5, 21/10)</span>