inequality could be used to find the number of models Walt builds. Correct option B).
<u>Step-by-step explanation:</u>
Here we have , Dwight and Walt are building model cars. Dwight builds 7 fewer models than 4 times the number Walt builds.Dwight builds at most 9 models. We need to find Which inequality could be used to find the number of models Walt builds . Let's find out:
Let the the number Walt builds is x , So Dwight builds 7 fewer models than 4 times the number Walt builds i.e.
⇒ 
But , according to question Dwight builds at most 9 models i.e.
⇒
⇒ 
⇒ 
⇒ 
Therefore , inequality could be used to find the number of models Walt builds which is Dwight builds at most 9 and Walt builds at most 4 .
Answer: Hello mate!
The partition of a set is defined as a partition of the set into a nonempty subset, where the set itself is a subset of himself, then the set is a partition of himself.
a) in this we have a set of two objects; A = (1,2) the partitions of this set are: (∅), (1), (2) and (1,2). Where (∅) is the null set.
b) Now we have a set of three objects; B = (a,b,c) the partitions of this set are: (∅), (a), (b), (c), (a,b), (a,c), (b,c), (a,b,c)
Answer:
$20.64
Step-by-step explanation:
if you cut 61.92 in to thirds
61.92/ 3= 20.64
so if Sarah's friends payed 2/3 of the bill Sarah herself payed 1/3 which is $20.64
I must confess that I was about to pass this question by, but I was captured by the respectful and dignified way in which you asked for help.
A careful reading of the problem gives you two equations in two unknowns, which you can then solve as simultaneous equations. Here's how it looks:
Call 'C' the price of the senior <u>C</u>itizen ticket.
Call 'S' the price of the <u>S</u>tudent ticket.
On the first night . . . 10 C + 12 S = 208
On the second night . . . 8C + 3 S = 74
Those are your two simultaneous equations. Now the idea is to multiply or divide each side of one equation in such a way that when you add or subtract it from the other equation, one of the variables will become a zero quantity ... you'll be left with an equation in one variable, which you can easily solve. THEN, knowing the value of one variable, you can put it back into one of the original equations,and find the value of the other variable.
This all sounds more complicated than it is. Here's how it goes:
We have . . .
10 C + 12 S = 208 and
8C + 3 S = 74
I'm going to multiply each side of the second equation by 4, and then write it under the first one:
10 C + 12 S = 208
32 C + 12 S = 296
Now, subtract the lower equation from the upper one, and you get . . .
- 22 C + 0 = - 88
Divide each side of this one by -22 and you have <em>C = $4.00</em> .
THAT's what you need, to blow the whole problem wide open. Knowing
the value of 'C', let's substitute it into the equation for the first night:
10 C + 12 S = 208
10(4) + 12 S = 208
40 + 12 S = 208
Subtract 40 from each side : 12 S = 168
Divide each side by 12 : <em>S =</em><em> $ 14.00 </em>.
Finally, as we look over our results, and see that Students have to pay $14 to see the show but Seniors can get in for only $4 , we reflect on this ... or at least I do ... and realize that getting old is not necessarily all bad.
Answer:
4900
Step-by-step explanation:
70^2 means 70*70
70*70=4900
