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3 years ago

6

The length of a rectangular parking lot at the airport is 2/3 mile. If the area is 1/2 square mile, what is the width of the par

king lot?

2 answers:

IrinaVladis [17]3 years ago

8 0

Answer:

3/4

Step-by-step explanation:

professor190 [17]3 years ago

3 0

I multiplyed i think the awnser maybe
0.3333 is awnser

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the length of a rectangle is 9 centimeters more than the width. the area is 112 square centimeters. find the length and width of

NeX [460]

Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)

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3 years ago

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What is the area of the shaded part of the figure?

adoni [48]

Oh all u do is just do the triangle the subtract the square from that

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3 years ago

Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).

Mariulka [41]

Answer:

$\bigl(\frac{3}{2},-5\bigr)$

or in decimal form

$(1.5,-5)$

Step-by-step explanation:

The midpoint of the line with endpoints $(x_1,y_1)$ and $(x_2,y_2)$ is $\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)$ . just take the average between the points

so given the points (1,0) and (2,-10)

$x_1=1$

$y_1=0$

$x_2=2$

$y_2=-10$

the midpoint is found as follows:

$\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)$

$\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)$

$\bigl(\frac{3}{2},\frac{-10}{2}\bigr)$

$\bigl(\frac{3}{2},-5\bigr)$

or in decimal form

$(1.5,-5)$

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4 years ago

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Snezhnost [94]

The correct answer should be steeper

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4 years ago

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Can someone slove this please

Morgarella [4.7K]

Hope this helps u.!!!

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4 years ago