3 years ago

How do you reduce 6 33/16

Mathematics

2 answers:

Marina86 [1]3 years ago

7 0

33/6=5 1/2
6+5 1/2= 11 1/2 is your final answer. Hope it help!

UkoKoshka [18]3 years ago

3 0

When you see the fraction 33/16, you realize that 33 divided by 16 is 2 remainder 1, so you add the 2 to the original 6, then put the remainder 1 on top of 16 ,which gives you 8 1/16

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2 years ago

<img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20ln%205" id="TexFormula1" title="e^{2x} = ln 5" alt="e^{2x} = ln 5" align=

KiRa [710]

$e ^{2x} = ln5$

Solve for the real domain

$e ^{2x} = ln(5)$

if $f(x) =g(x),$ then $ln(f(x))= ln(g(x))$

$ln(e ^{2x} ) = ln(ln(5))$

Solve : <span> $ln(e ^{2x} ) = ln(ln(5))$
</span>
use the logarithmic definition :

$ln(e^{f(x)} ) = f(x)$

$ln(e^{2x} ) = 2x$

$2x=ln(ln(5))$

Divide both sides by 2 :

$\frac{2x}{2} = \frac{ln(ln(5))}{2}$

$x= \frac{ln(ln(5))}{2}$

hope this helps!

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3 years ago

Please help this is due in 4 hours

vovikov84 [41]

X=14
Y=14
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The reason is because if you see 8 and 6 you can see that the lines are equivalent so I just assumed that the missing lines are 8 and 6. So I added the number up causing x and y to be 14 then for perimeter I simply just multiplied 14x4 which is 56.

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3 years ago