Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Hello from MrBillDoesMath!
Answer: b = 4, h = 13
Discussion:
For a triangle with base b" and height "h, the area formula is
A= (1/2)bh.
In our case A = 26, h = 5b-7, so
26 = (1/2) b (5b-7). Multiply both sides by 2:
26*2 = b(5b-7) =>
52 = b(5b-7) =>
52 = 5b^2 - 7b => (subtract 52 from both sides)
5b^2 - 7b - 52 = 0. This factors as follows:
(b - 4) (5 b + 13) = 0 (use quadratic formula to find this)
so b = 4 and h = 5b -7 = 5*4 - 7 = 13
Thank you,
MrB
By exterior angle of triangle:
17x+4+8x+1=80
x=3
Answer:
the answer is 0.24 jjjjjjjjjjjjjj
Answer:
A) 30
Step-by-step explanation:
3*10=30
A 30
