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s344n2d4d5 [400]
3 years ago
6

Draw to show how you can use model to compare 345 and 391

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
You could use graphs like hundreds graphs ;/
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PLS HELP ASAP WILL GIVE POINTS AND BRAINLIEST THANK YOU.
kifflom [539]
this is an awkward gather pic, that guy with the blue sweatshirt reminds me of a friend from my school. Although what you should do is try to give people more space for people to fit in right in the picture. Maybe like for the short kids should go to the front and the talk kids go to the back. This is just scram.bled
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3 years ago
I need to find and write the equation for the problem.
Julli [10]
0.8p - 50 < = 150
0.8p < = 150 + 50
0.8p < = 200
p < = 200/0.8
p < = 250

the reason I set it up this way is because when it is 20% off, u r actually paying 80% of the original price (p)....80% of the original price is written as 0.8p...then u subtract ur 50 dollar discount coupon...- 50.....and if all she can spend is 150....it would be less then or equal to 150. So the most she can spend on the phone is 250

7 0
2 years ago
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WILL GIVE BRAINLIEST, PLEASE HELP ASAP!!! MY LIFE DEPENDS ON THIS!!!
ahrayia [7]

h(x) = 3 * (2)^x

Section A is from x = 1 to x = 2

h(1) = 3 * (2)^1 = 3 * 2 = 6

h(2) = 3 * (2)^2 = 3 * 4 = 12

so

the average rate of change  = (12 - 6)/(2 - 1) = 6


Section B is from x = 3 to x = 4

h(3) = 3 * (2)^3 = 3 * 8 = 24

h(4) = 3 * (2)^4 = 3 * 16 = 48

so

the average rate of change  = (48 - 24)/(4 - 3) = 24


Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

the average rate of change of section B is 24 and the average rate of change of section A is 6

So 24/6 = 4

The average rate of change of Section B is 4 times greater than the average rate of change of Section A

It's exponential function, not a linear function; so the rate of change is increasing.

7 0
3 years ago
What is the simplified form of the expression k^3(k7/5)^-5
saveliy_v [14]
The expression can be simplified as:

k^3(k7/5)^-5
= k^(3+-5) * (7/5)^-5
(Collecting the powers of k at one side and the constants at other side)
= k^-2 * (5/7)^5
(Solving thr integer powers)
= k^-2 * (3125/16807)
4 0
3 years ago
What was your speed if you drove 325 miles in 5 1/4 hours?
Alexus [3.1K]

Answer:

62 miles per hour speed if you drove 325 miles in 5 1/4 hours

Step-by-step explanation:

Using formula:

\text{Speed} = \frac{\text{Distance}}{\text{Time}}

As per the statement:

if you drove 325 miles in 5 1/4 hours

⇒\text{Distance}=325 miles

and

Time = 5\frac{1}{4} = \frac{21}{4} = 5.25 hours

Then by above formula we have;

\text{Speed} = \frac{325}{5.25}=61.90 miles per hour

Therefore, 61.90 ≈ 62 miles per hour speed if you drove 325 miles in 5 1/4 hours

4 0
3 years ago
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