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Zielflug [23.3K]
3 years ago
15

Greatest to least 0.65 0.6 0.5 0.5

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:

0.65, 0.6, 0.5, 0.5

Step-by-step explanation:

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To find the distance between (17,3) and (17,−5), Marcia used the following equation. Is Marcia correct? Explain. D=|3−(−5)|=8
Bumek [7]

Answer:

Step-by-step explanation:

The formula for finding the distance between two points is expressed as shown

D = √(x₂-x₁)²+(y₂-y₁)²

Given the coordinate (17,3) and (17,−5), from the coordinates x₁ = 17, y₁ = 3, x₂ = 17 and y₂ = -5.Substituting the values given into the formula;

D = √(17-17)²+(-5-3)²

D = √0²+(-8)²

D = √64

D = 8

According to the result gotten, it can concluded that Marcia is correct although she didn't use the right expression to calculate her distance. She should have taken the square root of the sum of the square of difference in the coordinates axis according to the formula used.

8 0
3 years ago
Is 0.06 greater than 0.0582
Art [367]

Yes, 0.06 is greater than 0.0582.

If we look at the hundreths place, we can see 6 and 5. 6 is greater than 5 which proves that 0.06 is greater.

Best of Luck!

5 0
3 years ago
What are the integer solutions to the inequality below?<br> 9 &lt;_ 2x – 1&lt; x +7
kompoz [17]
the answer is 010/99 hsndnejdi
6 0
3 years ago
URGENT i need quick math help rn please:)
Kruka [31]
Multiplicity 2 means you're using that same root twice.  So we will FOIL out (x+1)(x+1)(x-3).  Doing that multiplying gives us  x^3+2x^2+x-3x^2-6x-3.  Combining like terms gives us the third degree polynomial we are looking for:  x^3-x^2-5x-3
3 0
3 years ago
3. Evaluate the following:
Darina [25.2K]

Answer: See below

Step-by-step explanation:

<u>Question 3:</u>

a) \ $S=1$ \ yields \ $(1,3)$ \\ \\b)  \ $S=3$  \ yields \ $(3,1)$ \\  \\ c)  \ $x(\sqrt{10})=\sqrt{10}$ \\ \\d) $y(\sqrt{10}+\sqrt{5})=1$ \\ \\e) $x(2)=2$ \\ \\f) $y(2,5)=1$ \\

<u>Challenge:</u>

\begin{aligned}&x(s)=s \quad ,s \in[0,4] \\&y(s)=\left\{\begin{array}{cc}3 s & , s \in[0,1] \\5-2 s &, s \in[1,2] \\1 & s \in[2,4]\end{array}\right.\end{aligned}

5 0
2 years ago
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