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2 years ago

Find the area of the quadrilateral DEFG.

Mathematics

1 answer:

Mariulka [41]2 years ago

6 0

Answer:

it's 56 because you times 8 and 7 together. I think

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The point (–3, –4) is reflected across the x-axis. What quadrant is the reflected point located? A. Quadrant I B. Quadrant II C.

Natali5045456 [20]

Answer:

Step-by-step explanation:

Since (-3, -4) is in Quadrant III and the reflected point will be "flipped" vertically the answer is Quadrant II.

5 0

3 years ago

What is the equation of the line that has a slope of 0 and passes through the point (6,-8)

Fofino [41]

$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=0(x-6)\implies y+8=0\implies y=-8$

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3 years ago

Read 2 more answers

A line with a slope of 0 contains the point (3,4) . The point -2,? is also on the line. What is the missing y-coordinate?

KatRina [158]

Answer:

Step-by-step explanation:

If the slope is 0, the line is horizontal and the y-coordinate is 4 for all x values.

Thus the missing y-coordinate is 4.

8 0

3 years ago

Badal has 120 cm 3 of water. He wants to pour it into a rectangular vase that is 4 cm high, 4 cm wide, and 5 cm long. Can he pou

Anestetic [448]

Answer:

volume= 4×4×5

Therefore he can't pour all the water into the vase because the amount of water is 120cm³ whilst the vase is 80. An amount of water as that can't fill the vase

6 0

3 years ago

Volume of a cone = r²h,

inessss [21]

Answer:

7.5 m 457.5 $\pi$ $m^{2}$

Step-by-step explanation:

First, visualize the original cone and the smaller cone as overlapping similar triangles. The scale factor of the original cone to the smaller cone is 50:40, so if the smaller cone has a radius of 6 m, then the radius of the original cone would be 7.5 m.

The volume of the frustum is the volume of the original cone minus the volume of the smaller cone. The formula for the volume of a cone is V = $\frac{1}{3} \pi r^{2}h$ .

Original Cone = $\frac{1}{3} \pi r^{2}h$ = $\frac{1}{3} \pi *7.5^{2}*50$ = 937.5 $\pi$

Smaller Cone = $\frac{1}{3} \pi r^{2}h$ = $\frac{1}{3} \pi *6^{2}*40$ = 480 $\pi$

Frustum = 937.5 $\pi$ - 480 $\pi$ = 457.5 $\pi$

6 0

2 years ago