2 years ago

Find the area of the quadrilateral DEFG.

1 answer:

6 0

Answer:

it's 56 because you times 8 and 7 together. I think

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dezoksy [38]

Area = (length) x (width)

Area = (10-ft) x (7-ft) = 70 ft²

(Width) / (Area) = (7-ft) / (70 ft²) = 1 / 10-ft .

4 0

3 years ago

zheka24 [161]

500 = 2 * 2 * 5 * 5 * 5

5 0

3 years ago

yuradex [85]

Equation: 3x+9=42

3x=42-9=33

<span>Answer: x=33/3=11

Hope this helps!!
</span>

3 0

3 years ago

Nina [5.8K]

X= 7/93 or roughly 0.07526...

7 0

3 years ago

natta225 [31]

We have been given that a right △ABC is inscribed in circle k(O, r).

m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.

First of all, we will draw a diagram that represent the given scenario.

We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.

We will use sine to find side AB.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(30^{\circ})=\frac{AC}{AB}$

$\text{sin}(30^{\circ})=\frac{18}{AB}$

$AB=\frac{18}{\text{sin}(30^{\circ})}$

$AB=\frac{18}{0.5}$

$AB=36$

Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is $\frac{36}{2}=18$ .

Therefore, the radius of given circle would be 18 cm.

8 0

3 years ago