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marta [7]
3 years ago
10

3x2 +x=10 what’s the answer?

Mathematics
2 answers:
babymother [125]3 years ago
5 0

Step-by-step explanation:

so 3 x 2 is 6

6 add x is 6x

6x = 10

divide by 6 or 10 on both sides to get ur answer

hope this helps

i would appreciate it if u could heart my answer and give it 5 stars or maybe even give it brainliest pls i beg u thx !!!!! : )

Alex17521 [72]3 years ago
3 0

Answer:

Step-by-step explanation:

3 × 2 + x = 10

6 + x = 10

x = 10 -6

x = 4

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(2, -2)

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x = 2

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Find the percent change 50 is decreased to 14.
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<h2>50, percentage decreased by 14% (percent) of its value = 43</h2>
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Select all of the statements that are true about f(x) =
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3 years ago
The height of a triangle is 4 m less than its base. The area of the triangle is 48 m^2.
masya89 [10]

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Step-by-step explanation:

Let x = base measurement; then height = (x-4).

 

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A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
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