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I am Lyosha [343]
3 years ago
11

2,3,4,5,6,7,8,9, 11, 13, 17, 19 Min: Q1 and Q3 Med: Max:

Mathematics
1 answer:
icang [17]3 years ago
5 0

Answer: Min: 2, Q1: 4.5, Med: 7.5, Q3: 12, Max: 19

Step-by-step explanation:

If you have a graphing calculator click on the stat button and then 1, which says edit. This will bring you to a list input all the numbers into L1. When your done putting in the numbers click the stat button again but then use the left arrow to go to calc, click on that. Then click 1, which says 1-Var Stats, this will show you all the statistical information you need to know about your list of numbers

The min is the smallest number

The max is the largest number

The median is the middle number, if doing this by hand be sure there are the same amount of numbers on each side

Q1 is the middle number between the min and the median

Q3 is the middle number between the max and the median

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Two positive, consecutive, odd integers have a product of 143. set up an equation to then solve for the integers.
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Step-by-step explanation:

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<h2>Question:- Area of the given diagram</h2>

<h2>Answer :- </h2>

Divide the diagram as shown in attachment.

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Area = 1× 12 = 12 unit²

Now find the Area of the remaining triangle with sides 12,13,5 units

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Now put the value as -> base= 5 and height= 12

Area =  \frac{1}{2}  \times base  \times height \:  \\ Area =  \frac{1}{2}  \times 5 \times 12 \\ Area =  \frac{1}{ \cancel2}  \times 5 \times  \cancel{12}^{ \:  \: 6}  \\ Area = 5 \times 6 \\ Area = 30 \: units^{2}

Now add both areas for your answer

Area{ \tiny{1}} = 12 {units}^{2}  \\ Area{ \tiny2} = 30 {units}^{2}  \\ Area{ \tiny{total}} = Area{ \tiny{1}} + Area{ \tiny{2}} \\ Area{ \tiny{total}} = 12 + 30 = 42 {units}^{2}

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