The answer for this problem is clarified through this, the
system is absorbing (+). And now see that it uses that the SURROUNDINGS are
doing 84 KJ of work. Any time a system is overshadowing work done on it by the
surroundings the sign will be +. So it's just 12.4 KJ + 4.2 = 16.6 KJ.
Answer:
a = (V2 - V1) / t = (0 - 14.6) / 3 = -4.87 m/s^2
It might be useful to convert 14.6 m/s to mph
14.6 m/s * 39.37 in/m = 575 in /s
575 in/s / 12 in/ft = 47.9 ft/sec
47.9 ft/s / 88 ft/sec * 60 mph = 32.6 mph
743 divides by djhd fjhfjfjsa 3883
Answer:
19.33°C
Explanation:
To find the value of T you use the following formula:
v: speed of sound
To calculate v you use:
λ: wavelength = 0.651m
f: = 545Hz
by replacing :
Finally, by replacing in the first formula you obtain:
T = 19.33°C
Answer:
The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J
Explanation:
The given variables are
Work done = 550 J
Volume change = V₂ - V₁ = -0.5V₁
Thus the product of pressure and volume change = work done by gas, thus
P × -0.5V₁ = 500 J
Hence -PV₁ = 1000 J
also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂
Also to compress the gas by a factor of 11 we have
P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11 = 909.091 J of work
