Answer:
s = 1800 m = 1.8 km
Explanation:
The distance, the speed, and the time of reach of the sound are related by the following formula:
where,
s = distance
v = speed
t = time
FOR WATER:
---------------------- eq (1)
where,
s = distance between ship and diver = ?
= speed of sound in water = 1440 m/s
t = time taken by sound in water
FOR AIR:
---------------------- eq (2)
where,
s = distance between ship and diver = ?
= speed of sound in water = 344 m/s
t + 4 s = time taken by sound in water
Comparing eq (1) and eq (2),because distance remains constant:
t = 1.25 s
Now using this value in eq (1):
<u>s = 1800 m = 1.8 km</u>
Answer:
correct option is a. 0.2 mA toward D
Explanation:
given data
B carries = 1.5 mA
C carries current = 1.3 mA
solution
we take positive direction of current going away from the point D
and negative direction of current coming towards point D
so we use here kirchoff's current law
that is
iA + iB + iC = 0 ......................1
iA + 1.5 + (-1.3) = 0
iA = - 0.2 mA
so that current in wire A is 0.2 mA towards point D
correct option is a. 0.2 mA toward D
Answer:
no mam
Explanation:
the answer to the question is
Printer could be a machine
Answer:
The slopes shows that the direction of the field is from -2 to +2, with three point charges, q₁, q₂ and q₃ at -2, 0 and +2 respectively.
Explanation:
Given;
The slope, dy/dx = 2x(y-6) - 4
2x(y-6) - 4 = 2xy - 12x - 4, divide through by 'x'
dy/dx = 2y -12 - 4/x
The slopes of the linear elements on the lines, x =0, y = 5, y = 6, y = 7.
At x = 0, and y = 5
dy/dx = 2y -12 - 4/x
dy/dx = 2(5) - 12 = -2
At x = 0, and y = 6
dy/dx = 2y -12 - 4/x
dy/dx = 2(6) - 12 = 0
At x = 0, and y = 7
= 2y -12 - 4/x
dy/dx = 2(7) - 12 = 2
Therefore, the slopes shows that the direction of the field is from -2 to +2, with three point charges, q₁, q₂ and q₃ at -2, 0 and +2 respectively.
